A number leaves reminder 6 when divided by 10. What is the remainder when the number is divided by 5? Justify your reasoning.
209
11.5
The smallest number that can be divided by 2 3 4 5 6 7 8 and always give you a remainder of 1 is 841
57
2519
6
No number can satisfy these conditions: To have a remainder of 1 when divided by 6, the number must be odd (as all multiples of 6 are even and an even number plus 1 is odd) To have a remainder of 2 when divided by 8, the number must be even (as all multiples of 8 are even and an even number plus 2 is even) No number is both odd and even. → No number exists that has a remainder of 1 when divided by 6, and 2 when divided by 8.
this is a easy question....
yes
60 6*9+6=60 7*8+4=60
301 is one such number.