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The chemical formula of magnetite is Fe3O4.
Iron: 74,41 %
Oxygen: 27,59 %

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Q: What is the percent composition of magnetite?
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How would you determine the chemical composition of magnetite?

Fe2O3


Is magnetite an artificial magnet?

No, magnetite is a naturally occurring mineral that exhibits magnetic properties due to its composition of iron oxide. It is not an artificial magnet.


What is the chemical composition of magnetite?

The iron itself is usually found in the form of magnetite(Fe3O4), hematite (Fe2O3), goethite (FeO(OH)), limonite (FeO(OH).n(H2O)) or siderite (FeCO3). Source:Wiki


Why is cumberlandite magnetic?

Cumberlandite is magnetic due to the presence of magnetite, an iron oxide mineral, in its composition. Magnetite has magnetic properties that make cumberlandite attracted to magnetic fields.


What is an iron ore called?

Iron ore is commonly referred to as hematite, magnetite, or taconite, depending on its composition and characteristics.


What is the percent composition of oxygen in the magnetite Fe3O4?

The molar mass of Fe3O4 is 231.55 g/mol. The molar mass of oxygen is 16.00 g/mol. There are 12 oxygen atoms in Fe3O4, so the total mass of oxygen in Fe3O4 is 192.00 g. Therefore, the percent composition of oxygen in Fe3O4 is (192.00 g / 231.55 g) x 100 = 82.97%.


Which is the richest iron ore?

Magnetite - It is an Oxide of Iron and yields 72 percent metal.


What percent of magnetite is left in the world?

It is estimated that about 1-2% of the total worldwide reserves of magnetite remain. However, this can vary based on factors such as extraction rates and new discoveries.


What is the percent composition in lithium and bromine?

The percent composition of lithium in lithium bromide (LiBr) is approximately 7.7%. The percent composition of bromine in lithium bromide is approximately 92.3%.


What is the percent composition of c5h12?

The percent composition of C5H12 is: carbon (C) = 83.78%, hydrogen (H) = 16.22%.


What is the percent composition for 29.0 g of Argon combine completely with 4.30 g of Sulfur?

To find the percent composition, first calculate the total mass by adding the masses of Argon and Sulfur. Then, determine the percent composition of each element by dividing the mass of that element by the total mass and multiplying by 100. In this case, the percent composition of Argon is about 87.1%, and the percent composition of Sulfur is about 12.9%.


What is the percent of a composition of a compound containing 8.6g of Be and 52.4g of I?

To find the percent composition of each element in the compound, you first calculate the molar mass of Be (9.01 g/mol) and I (126.90 g/mol). Then, calculate the percent composition of each element by dividing the mass of the element by the total molar mass of the compound and multiplying by 100. The percent composition of Be is 5.14% and the percent composition of I is 94.86%.