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+3 for each Al, -2 for each O and +6 for each Cr

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11y ago
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5mo ago

The oxidation number of aluminum (Al) is +3, the oxidation number of chromium (Cr) is +3, and the oxidation number of oxygen (O) is -2. Therefore, in Al2Cr6O21, the total oxidation number would be +6 from aluminum, +18 from chromium, and -42 from oxygen, resulting in a net oxidation number of -18 for the compound.

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Q: What is the oxidation number of Al2Cr6O21?
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