1% (presumably m/v) glucose solution would contain 1 g of glucose per 100 ml of solution. Therefore the conversion of 1 g / 100 ml to units of mol/L requires that we divide by the molar mass and multiply by the conversion factor of ml to L. Therefore: (1 g / 100 ml) * (1 mol / 180.16 g) * (1000 ml / 1 L) = 0.0555 M = 0.06 M.
ANSWER:"e is a measure of the amount of light absorbed per unit concentration".Molar absorbtivity is a constant for a particular substance, so if the concentration of the solution is halved so is the absorbance, which is exactly what you would expect.The formula for the molar absorptivity is given as followings:A=ecle=A/cle = the molar absorptivitywhere A is known as the A is known as the absorbance, l measures the length of the solution the light passes through,c is theconcentration of solution in mol /dm^3.Remember that the absorbance of a solution will vary as the concentration or the size of the container varies. Molar absorptivity compensates for this by dividing by both the concentration and the length of the solution that the light passes through. Essentially, it works out a value for what the absorbance would be under a standard set of conditions - the light travelling 1 cm through a solution of 1 mol dm-3. a
To convert to per litre we multiply weight by 2. This gives 40 grams per litre. 40g divided by 40g/mol is a 1 molar solution.
Answer: 7 x 10-3 g glucoseProcess below:First convert 40 µmol to moles. 1 µmol = 1 x 106 mol.40 µmol x (1 mol)/(1 x 106µmol) = 4 x 10-5 molMultiply 4 x 10-5 mol by the molar mass of glucose (180.156 g/mol).4 x 10-5mol glucose x (180.156 g glucose)/(1 mol glucose) = 7 x 10-3 g glucose
Molar mass of Magnesium Iodide=151.2g/mole 1 Molar solution=151.2g/L 0.5 M solution=75.6g/L=75.6g/1000mL=37.8g/500mL
Relative molar mass, temperature, and concentration difference/gradient.
The isotonic coefficient for NaCl can be calculated by dividing the concentration of the glucose solution (14M) by the concentration of the NaCl solution (0.7M). This gives an isotonic coefficient of 20 for NaCl, meaning that a solution of 0.7M NaCl is isotonic with a 14M glucose solution with respect to hemolysis.
To make a molar solution from a 32% hydrochloric acid solution, you would need to first calculate the molarity of the 32% solution. Molarity is calculated by multiplying the percent concentration by the density of the solution and dividing by the molar mass of the solute. Once you determine the molarity, you can then dilute the solution to the desired molar concentration by adding the appropriate amount of solvent (usually water).
This is a molar concentration.
To make a 1 molar solution of glucose in 0.5 L of water, you would need to dissolve 90.1 grams of glucose powder. This is because the molar mass of glucose (C6H12O6) is approximately 180.2 g/mol, and for a 1 molar solution in 0.5 L of water, you would need 1 mole of glucose, which is 180.2 grams.
To find the molality of a solution, you need the mass of the solvent (usually water) in kilograms and the number of moles of solute (glucose). Given that the solution is 7.80% glucose by weight, you can calculate the mass of glucose in the solution and then convert it to moles using the molar mass of glucose. From there, you can find the molality by dividing the moles of glucose by the mass of the solvent in kilograms.
The molar concentration of nitric acid can vary depending on the specific solution. However, a common concentration of nitric acid used in laboratories is around 16 M (molar). This means there are 16 moles of nitric acid in 1 liter of solution.
The molar mass of glucose is 180.16 g/mol. To find the number of moles in 80 g, divide the mass by the molar mass: 80 g / 180.16 g/mol = 0.444 moles. The molar concentration is then moles/volume, so 0.444 moles / 2 L = 0.222 M.
The concentration of the solute is 0,5 molar.
Not necessarily or even usually. The term "one molar" refers to the concentration of the acid added and does not have anything to do with the concentration of ferrous ions.
A molar solution is a solution with a known concentration expressed in moles of solute per liter of solution, while a normal solution is a solution with a known concentration expressed as gram-equivalents of solute per liter of solution. Molar solutions are commonly used in chemistry, while normal solutions are used more in analytical chemistry and chemical analysis.
A 1 molar solution refers to a solution that contains 1 mole of solute dissolved in 1 liter of solvent. This concentration is commonly used in chemistry to describe the amount of a substance dissolved in a certain volume of solution. It is a way to express the concentration of a substance in a solution.
Semi-molar refers to a solution that is halfway between being molar (having a concentration of 1 mole of solute per liter of solution) and being dilute. It typically refers to a solution where the concentration falls between 0.1 to 1 mole per liter.