You obtain the absolute minimum of the function when x=0. (0^4)-2 =0-2=-2. So, the lower bound of the function is -2.
sqrt(x4) = x4/2 = x2
24
N = x4 x8 = x4+4 = (x4)2 = N2
x4 + 7x2 - 60 = x4 + 12x2 - 5x2 - 60 = x2(x2 + 12) - 5(x2 +12) = (x2 - 5)(x2 +12)
2% (50 x4) / 100
j
0.039
4.46 is a fixed number: it has no upper nor lower bound. To 2 dp it is 4.46
sqrt(x4) = x4/2 = x2
264
the answer is 2
x4
24
N = x4 x8 = x4+4 = (x4)2 = N2
(x - 2)(x + 2)(x^2 + 4)
x4 - 4x3 - 12x2 -32x + 64 (x - 4)(x + 2)(x + 2)(x - 4)
(x^2 - 2x + 2)(x^2 + 2x + 2)