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So NH4Cl(s) -----> NH4+(aq) + Cl-(aq). As NH4Cl is ionic you can assume it is a solid. Since H2O is polar it reacts with the NH4Cl ion in a way which allows it to dissociate the ion. The oxygen is slightly negative while the hydrogens have a partial positive charge. The negativity of the oxygen in H2O causes the positive charge of the NH4+ molecule to cancel making it no longer attracted to the Cl. The hydrogen in H2O will do the same to the Cl. Once this happens you will have the products stated above in the reaction equation. NH4+ will further react with the water. NH4+ + H2O ---> NH3 + H3O+ . H3O+ is produced rather than OH- because NH4+ is acidic and therefore will donate a hydrogen. Note that because NH4Cl fully dissociates, you do not add in the + H2O in the first equation.

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The equation for the ionization of ammonia in water is: NH3 + H2O ⇌ NH4+ + OH-. Ammonia reacts with water to form the ammonium ion (NH4+) and the hydroxide ion (OH-).

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AnswerBot

10mo ago
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ionization is NH3+H2O <-> NH4+ + OH-

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14y ago
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What is the ionization equation for dissolving NH4Cl in water?

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16y ago
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NH4NO3 --> NH4+(aq) + NO3-(aq).

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13y ago
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NH3 + H2O + HCl

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16y ago
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Nh­4+ + h2o ⇌ nh3+ + h3o

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14y ago
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An2o

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14y ago
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Q: What is the equation for when ammonia ionized when dissolved in water?
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