For the mother to have a non-albino offspring, she would need to have at least one dominant allele for the trait, so her genotype could be either Aa or AA. The father must have two recessive alleles (aa) to pass on albinism to the offspring. The albino offspring's genotype would be aa.
The woman's genotype would be heterozygous for the albino gene, as she would inherit one normal gene from her father and one albino gene from her mother. Therefore, her genotype would be Aa, where "A" represents the normal gene and "a" represents the albino gene.
The offspring being albino can be explained by the principle of dominance and recessiveness. In this case, the albino trait is recessive, so it only shows up when an individual inherits two copies of the albino allele. Since both parents are heterozygous, they carry one normal allele and one albino allele, resulting in a 25% chance of producing an albino offspring.
Albinism is a sex-linked trait. Accordingly, the description of "heterozygous male" doesn't make sense. The sex chromosomes for males are XY, and usually genetic disorders are passed down by the X chromosome (which is the case for albinism). So in the problem, we aren't sure whether the male is XaY or XAY. It would be more helpful to know if the male was albino or not; we would then immediately know his genotype. We can, however, figure out the genotype of the female. Because albinism is recessive, we can deduce that her genotyple is XaXa. But without knowing the male's genotype or phenotype, the offspring percentages cannot be calculated.
Albinism is a recessive trait, meaning that an albino person has the genotype AA, while a person who isn't albino has the trait Aa or AA. Two albino people (AA x AA) will have all albino children. Aa x AA will have a 50% probability of albino children, and 50% normal children who are carriers (Aa). AA x AA will have all normal children who are carriers (Aa). Aa x Aa will have 25% AA (normal/non carriers), 25% AA (albino), and 50% Aa (normal/carriers) offspring. AA x AA will have all normal children who are not carriers (AA).*A person who has the genotype Aa is a carrier because they carry the allele (a) for albinism but they are not albino. The allele (A) is dominant so it covers the (a) allele.
For the mother to have a non-albino offspring, she would need to have at least one dominant allele for the trait, so her genotype could be either Aa or AA. The father must have two recessive alleles (aa) to pass on albinism to the offspring. The albino offspring's genotype would be aa.
The woman's genotype would be heterozygous for the albino gene, as she would inherit one normal gene from her father and one albino gene from her mother. Therefore, her genotype would be Aa, where "A" represents the normal gene and "a" represents the albino gene.
Each parent is heterozygous for the gene.
The offspring being albino can be explained by the principle of dominance and recessiveness. In this case, the albino trait is recessive, so it only shows up when an individual inherits two copies of the albino allele. Since both parents are heterozygous, they carry one normal allele and one albino allele, resulting in a 25% chance of producing an albino offspring.
Albinism is a sex-linked trait. Accordingly, the description of "heterozygous male" doesn't make sense. The sex chromosomes for males are XY, and usually genetic disorders are passed down by the X chromosome (which is the case for albinism). So in the problem, we aren't sure whether the male is XaY or XAY. It would be more helpful to know if the male was albino or not; we would then immediately know his genotype. We can, however, figure out the genotype of the female. Because albinism is recessive, we can deduce that her genotyple is XaXa. But without knowing the male's genotype or phenotype, the offspring percentages cannot be calculated.
Temperature affects the C gene codes for the enzyme tyrosinase, the first step in pigment production. The recessive alleles determine whether a cat is a complete albino or a temperature sensitive albino. These genes affect the color of the cats eyes and coat.
There is a very low percentage of having a albino child if you yourself are not albino ==you can have an albino baby==
Albinism is a recessive trait, meaning that an albino person has the genotype AA, while a person who isn't albino has the trait Aa or AA. Two albino people (AA x AA) will have all albino children. Aa x AA will have a 50% probability of albino children, and 50% normal children who are carriers (Aa). AA x AA will have all normal children who are carriers (Aa). Aa x Aa will have 25% AA (normal/non carriers), 25% AA (albino), and 50% Aa (normal/carriers) offspring. AA x AA will have all normal children who are not carriers (AA).*A person who has the genotype Aa is a carrier because they carry the allele (a) for albinism but they are not albino. The allele (A) is dominant so it covers the (a) allele.
Are you Albino?
There are white(albino) lions and one time I saw a white(albino)alligator!Or was it a crocodile...Many animals are albino.
I think it's genotype...
a shark thats an albino