The oxidation number of Cr in Cr3+ is +3. This is because each Cl ion has a charge of -1, and since the compound is neutral, the total positive charge from Cr must equal the total negative charge from the Cl ions.
Chromium (III) has a 3+ charge. Permanganate (MnO4-) Has a 1- charge. Therefore it takes 3 Permanganate anions to equal the charge of a Chromium (III) cation. This should be Cr(MnO4)3
The oxidation number of Cr in Cr2O7^2- is +6. This is because the overall charge of the dichromate ion is 2-, and each oxygen atom has an oxidation number of -2. By setting up and solving an equation representing the total charge of the ion, we can determine the oxidation number of Cr.
Cr(CN)2
The oxidation number of Cr in CrO4^2- is +6. This can be calculated by considering the overall charge of the ion (-2) and the known charge of the oxygen ion (-2 each).
+2
3 +
The oxidation number of Cr in Cr3+ is +3. This is because each Cl ion has a charge of -1, and since the compound is neutral, the total positive charge from Cr must equal the total negative charge from the Cl ions.
The oxidation state of chromium (Cr) in SrCr2O7 is +6. This can be determined by considering the overall charge of the compound (+2 from Sr and -7 from O), and then solving for the oxidation state of Cr to balance the charges.
Chromium (III) has a 3+ charge. Permanganate (MnO4-) Has a 1- charge. Therefore it takes 3 Permanganate anions to equal the charge of a Chromium (III) cation. This should be Cr(MnO4)3
The oxidation number of Cr in Cr2O7^2- is +6. This is because the overall charge of the dichromate ion is 2-, and each oxygen atom has an oxidation number of -2. By setting up and solving an equation representing the total charge of the ion, we can determine the oxidation number of Cr.
Cr(CN)2
The oxidation number of Cr in CrO4^2- is +6. This can be calculated by considering the overall charge of the ion (-2) and the known charge of the oxygen ion (-2 each).
The oxidation charge of chromium can vary, but common oxidation states include +2, +3, and +6.
It depends on the offense. You can find specific information here: http://www.statutes.legis.state.tx.us/Docs/CR/htm/CR.12.htm
The transition metal with 24 electrons is chromium (Cr) and its common ion with a +3 charge is Cr3+.
The oxidation number of Cr in Cr2O7^2- ion is +6. Each oxygen atom has a -2 charge, and the overall charge of the ion is 2-, so combining the charges gives -2*(-7) = -14. Since the overall charge is 2-, the oxidation number of Cr must be +6 to balance the charges.