The word equation for sodium bicarbonate is: sodium bicarbonate (sodium hydrogen carbonate) + acetic acid (vinegar) → water + carbon dioxide + sodium acetate.
The balanced chemical equation for the reaction is: CH3COOH + NaHCO3 → CH3COONa + H2O + CO2 This is a double displacement reaction, where sodium from sodium bicarbonate replaces hydrogen in acetic acid to form sodium acetate, water, and carbon dioxide.
The balanced chemical equation for the decomposition of sodium bicarbonate into sodium oxide, carbon dioxide, and water is: 2 NaHCO3 -> Na2O + CO2 + H2O
It doesn't need balancing - it's already balanced. NaHCO3 + NaOH → Na2CO3 + H2O
Yes. Sodium bicarbonate is a base.
The reaction between sodium hydroxide (NaOH) and acetic acid (CH3COOH) forms sodium acetate (CH3COONa) and water (H2O). The balanced chemical equation is: CH3COOH + NaOH -> CH3COONa + H2O.
The balanced chemical equation for the reaction between sodium bicarbonate (NaHCO3) and hydrochloric acid (HCl) is: NaHCO3 + HCl → NaCl + H2O + CO2
K2HPO4 + NaHCO3 --> K2NaPO4 + H2O + CO2 is the balanced equation for the reaction of dipotassium hydrogen phosphate and sodium bicarbonate. (All numbers should be subscripts). Dipotassium phosphate does not exist. Tripotassium phosphate, K3PO4 does, but it's not acidic and therefore does not react with sodium hydrogen carbonate (sodium bicarbonate).
The reaction of acetic acid and sodium hydroxide will form sodium acetate and water. The chloroform is not involved in the reaction and will remain unchanged. The balanced chemical equation for the reaction is: CH3COOH (acetic acid) + NaOH (sodium hydroxide) -> CH3COONa (sodium acetate) + H2O (water)
Acetic acid
The reaction between benzoic acid and sodium bicarbonate produces sodium benzoate, carbon dioxide, and water. The balanced chemical equation for this reaction is: C6H5COOH + NaHCO3 -> C6H5COONa + CO2 + H2O
I assume you mean you want the molecular formula for sodium bicarbonate - if you wanted a balanced equation, you would need another substance to react with But sodium bicarbonate = NaHCO3 While the above answer is help full I am going to assume that the question was what is the balanced equation for the decomposition of sodium bicarbonate. 2NaHCO3--> Na2CO3+CO2+H2O in further detail the reaction for this formula is not decomposition; it is, in fact, combustion because of the carbon dioxide and water in the products of the equation.