What is the Lewis structure of XeOF4?

Answer 1

Xenon (Xe) does not have to follow the octet rule because of its access to the 4d sublevel. Xe is placed in the center and single bonded to two fluorine atoms that are 180 degrees apart. There are 3 lone pairs on the Xe atom.

Answer 2

The Lewis structure of XeOF4 has xenon (Xe) as the central atom with an oxygen (O) atom double bonded to it and four fluorine (F) atoms single bonded around it. This molecule has 12 valence electrons.

Answer 3

Start with the Xe atom in the center. There are five single bonds, four attached to an F atom, and the last attached to the O atom. Each of those atoms has a pair of dots on the unbonded sides and the Xe atom has a pair of dots.

Answer 4

The dot structure starts with Xe in the center with five single bonds and a pair of dots 60 degrees apart. There are four F atoms and one O attached to the bonds, and each has three pairs of dots on their unbonded sides.

Answer 5

Xe is the central atom, while the 4 Fluorides surround it. Xe has 4 sigma bonds to the F. Each F has 3 lone pair electrons and Xe has an extra pair of lone pair electrons, making it's octet have 10 electrons instead of 8.

Answer 6

It has the Lewis structure of a molecule with an octahedral arrangement.

The lone pair around Xe is sterochemically inactive, allowing it to have this arrangement.

However, because of this lone pair XeF6 does not have a perfect octahedral arrangement. This does not change it's Lewis structure, but it does change its point group if that matters to you. It puts the molecule in the C3V point group instead of the Oh point group.

The structure of XeF6 is same as KrF6 and has no lone pairs.

XeF6 = Xe + 3F2 - trigonal structure

KrF6 = Kr + 3F2

Answer 7

F atoms are bonded sort of like a star shaped with respect to the Xe atom with two lone pairs at the top and bottom of the Xe atom, its a planar molecule. There is an overall negative charge of -1 on the molecule. The angle should be around 72 degrees.

Answer 8

Refer to the related link below for an illustration of the Lewis dot structure of xenon tetrafluoride (XeF4). The lines between atoms represent one pair of electrons, in which one electron comes from Xe and one comes from F.

Answer 9

Total valence electrons Kr + 6 (F) that is 8+6(7) = 50

We'll start bonding 6 F around Kr with single bonds and we'll be left with 38 electrons.

Now out of these 38 electrons 36 will be put around each F in the form of 3 lone pairs and remaining two electrons will be put on central Kr as a lone pair along with 6 bond pairs.

You're welcome

Answer 10

The dot structure starts with the Xe atom in the center. On each side, draw a single bond. On each bond, attach a single O atom with a pair of dots on each unattached side.