Basic as NaOH is a strong base.
A 50% purity solution of NaOH would contain 500 grams of NaOH per liter of solution. Given that the density is 1.53 g/mL, there would be approximately 327.5 grams of NaOH in one liter of solution (1.53 g/mL * 1000 mL).
To calculate the concentration of a 0.1 N NaOH solution, you need to know the molar mass of NaOH which is approximately 40 g/mol. Since 1 N solution is equivalent to 1 gram equivalent weight of the solute dissolved in 1 liter of the solution, a 0.1 N NaOH solution would contain 4 g of NaOH per liter of solution.
Heating NaOH before adding BaCl2 helps to dissolve NaOH completely in water, ensuring that no solid NaOH remains undissolved in the solution. This is important because the reaction between BaCl2 and NaOH requires the NaOH to be in solution to react with the BaCl2. Heating the solution can also speed up the reaction between NaOH and BaCl2.
The dissociation reaction of NaOH in water is as follows: NaOH (s) → Na+ (aq) + OH- (aq)
NaOH
This solution contain 26,3 g NaOH.
NaOH
No, NaOH (sodium hydroxide) does not contain H+ ions. When NaOH dissolves in water, it dissociates into Na+ and OH- ions, with OH- being the hydroxide ions that can accept H+ ions to form water in a chemical reaction.
Basic as NaOH is a strong base.
The molarity of a NaOH solution is determined by the concentration of NaOH in moles per liter of solution. It is calculated by dividing the moles of NaOH by the volume of solution in liters. For example, a 0.1 M NaOH solution would contain 0.1 moles of NaOH per liter of solution.
A 50% purity solution of NaOH would contain 500 grams of NaOH per liter of solution. Given that the density is 1.53 g/mL, there would be approximately 327.5 grams of NaOH in one liter of solution (1.53 g/mL * 1000 mL).
A hydroxide contain the group hydroxyl (-OH) and a metal; example: sodium hydroxide, NaOH.
Sodium hydroxide (NaOH) is polyatomic (contain atoms of Na, O and H).
5 M NaOH = 5 mol/L NaOH. 1 mol of NaOH = 40 g NaOH. You can get the number of grams by multiplying 5 mol/L and 40g/mol. This will give you 200g/L. Just multiply by the volume, which is 1 Liter, and you will get 200 g of NaOH.
To determine the grams of sodium hydroxide in 0.150 mol, you need to use the molar mass of NaOH, which is 40.00 g/mol (Na = 22.99 g/mol, O = 16.00 g/mol, H = 1.01 g/mol). 0.150 mol NaOH x 40.00 g/mol = 6.00 grams of NaOH.
To calculate the concentration of a 0.1 N NaOH solution, you need to know the molar mass of NaOH which is approximately 40 g/mol. Since 1 N solution is equivalent to 1 gram equivalent weight of the solute dissolved in 1 liter of the solution, a 0.1 N NaOH solution would contain 4 g of NaOH per liter of solution.