It has one nucleon.
It has no neutrons.
It has one proton.
When P-32 decays to S-32, a beta particle is emitted. This beta particle is an electron released during the conversion of a neutron into a proton within the nucleus of the atom.
In atomic structure, shells are energy levels where electrons are found, while subshells are smaller regions within shells where electrons with specific energy levels are located. Shells are labeled with numbers (1, 2, 3, etc.), while subshells are labeled with letters (s, p, d, f).
The particle with a -3 charge and 36 electrons is an ion of the element phosphorus (P). It has gained three extra electrons, resulting in a charge of -3.
The particle is an atom of selenium (Se). It has 34 protons and 34 electrons, since the number of protons equals the number of electrons in a neutral atom. The electron configuration given ("1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6") matches that of selenium.
We usually see p+ used for the proton. Remember that it's a hydrogen nucleus. It might appear as H+ to denote a hydrogen atom (actually an ion) that has lost its electron and is a lonely proton with its characteristic +1 charge. Note that a hydrogen nucleus can sometimes have one or even two neutrons stuck together with the proton. Just so ya know. Also, it can be written as 1 over 1 p
It has one nucleon it has no neutrons it has one proton
p
, ,p,;p;
Proton.
I am assuming that this is to do with the trajectory that is simplified to that of a particle which does not incur air resistance. If I have understood the question correctly, the particle travels under the influence of a constant force - assumed to be gravity which acts downwards. The model can be extended to allow for a constant force acting at an angle but the calculations then become more complicated. The particle is projected upwards, with the initial velocity, u ms-1, which makes an angle P with the horizontal. u is a variable such that the horizontal range of the particle is a constant. The vertical component of the initial velocity is u*sin(P) ms-1. The gravitational force, acting downwards, is -g ms-2. When the particle returns to the ground level, the vertical component of its velocity is -u*sin(P) ms-1. So if the particle returns at time t seconds, then t = [u*sin(P) - -u*sin(P)] /g = 2*u*sin(P)/g sec. The horizontal component of the velocity of the particle is a constant u*cos(P) ms-1. So during the time in flight, it travels u*cos(P)*2*u*sin(P)/g m = 2*u2*sin(P)*cos(P)/g m. This horizontal distance is constant, which implies that 2*u2*sin(P)*cos(P)/g is constant so that u2 is inversely proportional to sin(P)*cos(P). So let u = sqrt[k/sin(P)*cos(P)] ms-1 for some constant k. then its vertical component is u*sin(P) = sqrt[k/sin(P)*cos(P)]*sin(P) ms-1 = sqrt[k*tan(P)] Then at time T, its height is sqrt[k*tan(P)]*T - 0.5g*T2 I just hope this is correct!
The answer is 1/90.
When P-32 decays to S-32, a beta particle is emitted. This beta particle is an electron released during the conversion of a neutron into a proton within the nucleus of the atom.
Particle
A gamma ray is not an elementary particle, it is a high-energy photon. Photons are elementary particles that have zero rest mass and carry electromagnetic radiation.
particle
Particle velocityparticle displacementpolarizationpressureplasmas
Particle.