The first 6 multiples of 4 are: 4, 8, 12, 16, 20, and 24.
The multiples of 10 are: 1, 2, 5, 10 The multiples of 5 are: 1 and 5. The multiples of 6 are: 1, 2, 3, and 6. The multiples of 8 are: 1, 2, 4, and 8. The number that they all have in common is 1, so the lcd is one.
2, 4, 6, 8, 10, 12
8 of them.
Not always as for example 36 is a multiple of 4 but not of 8
Multiples of 6 end in 6, 2, 8, 4 or 0.
The LCM of 3, 4, 6, and 8 is 24 The multiples of 3 are 3, 6, 9, 12, 15, 18, 21, 24, and so on. The multiples of 4 are 4, 8, 12, 16, 20, 24, and so on. The multiples of 6 are 6, 12, 18, 24, and so on. The multiples of 8 are 8, 16, 24, and so on. So the LCM of 3, 4, 6, and 8 is 24.
Multiples of 8 are 8, 16, 24, 32, 40, 48... Multiples of 6 are 6, 12, 18, 24, 30, 36, 42, 48... Multiples of 4 are 4, 8, 12, 16, 20, 24, 28, 32, 36, 40... Multiples that 8, 6, and 4 have in common are 24, 48, 72...
The first 6 multiples of 4 are: 4, 8, 12, 16, 20, and 24.
The multiples of 4 are 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, and 48. The multiples of 6 are 6, 12, 18, 24, 30, 36, 42, and 48. Thus, the multiples of 4 that are not multiples of 6 are 4, 8, 16, 20, 28, 32, 40, and 44.
4 and 8 are multiples of 2. 6 and 9 are multiples of 3. 40 and 50 are multiples of 10.
For 4 It's 1,2,4 For 6 1,2,3,6 For 8 1,2,4,8
No, they are just multiples of 2.
No multiples of 24 are factors of 6.1, 2, 3, 4 and 8 are factors of 24 that are not multiples of 6.
24 Multiples of 6 are 6,12,18,24,30 Multiples of 8 are 8,16,24,32 So 24 is the smallest number that can be evenly divided by both 6 and 8.
Assuming you mean that you want the number of multiples of each, then for 1-100: number of multiples of 2 = 50 number of multiples of 3 = 33 number of multiples of 4 = 25 number of multiples of 6 = 16 number of multiples of 8 = 12 number of multiples of 9 = 11 Assuming you mean that you want the numbers that are multiples of 2, 3, 4, 6, 8 or 9, then some numbers may be multiples of more than one (for example 12 is a multiple of 2, 3, 4 and 6) and so a straight addition of the number of multiples of each cannot be done: Consider 2, 4 and 8 Every multiple of 4 or 8 is also a multiple of 2, so all the multiples of 4 and 8 are counted by the multiples of 2. Consider 3 and 9 Every multiple of 9 is also a multiple of 3, so all the multiples of 9 are counted by the multiple of 3 Consider 2, 3 and 6. Every multiple of 6 is an even multiple of 3, so are counted in both the multiples of 2 and 3. So the total number of multiples of 2, 3, 4, 6, 8 or 9 is the number of multiples of 2 plus the number of multiples of 3 minus the number of multiples of 6: For 1 to 100, Number of multiples of 2 = 50 Number of multiples of 3 = 33 Number of multiples of 6 = 16 So number of multiples of 2, 3, 4, 6, 8 or 9 in 1-100 is 50+33-16 = 67. Assuming you mean that they are multiples of all of 2, 3, 4, 6, 8 and 9, then they must be multiples of the lowest common multiple of 2, 3, 4, 6 ,8, 9 2 = 21, 3 = 31, 4 = 22, 6 = 2131, 8 = 23, 9 = 32 LCM = highest power of the primes used = 2332 = 72 Thus all numbers that are multiples of 2, 3, 4, 6, 8 and 9 are multiples of 72, which means between 1 and 100 only 1 number is a multiple of all of them, namely 72
Do you mean 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12? Do you want multiples of each one separately? e.g. multiples of 2, multiples of 3, multiples of 4? The answers to the times tables will do it if that is what you want. eg 2, 4, 6, 8, 10... 3, 6, 9, 12, 15... 4, 8, 12, 16, 20... etc.