The prime factors of 112 are: 2 and 7
The prime factors of 112 are 2 and 7
it has 4 factors
the prime factors of sum of 121 is 112 and 22
15125 = 53 * 112
The prime factors are: 2, 7
As exponents: 22*112 = 484
The factors of 48 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48.The prime factors of 48 are: 2 and 3.The factors of 112 are: 1, 2, 4, 7, 8, 14, 16, 28, 56, and 112.The prime factors of 112 are: 2 and 7.The factors of 144 are: 1, 2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 36, 48, 72, and 144.The prime factors of 144 are: 2 and 3.
As a product of its prime factors: 2*2*2*2*7 = 112
As a product of its prime factors: 2*2*2*2*7 = 112
To express 112 as a product of its prime factors, we first need to find its prime factorization. We can start by dividing 112 by the smallest prime number, which is 2. 112 ÷ 2 = 56. Then, 56 can be divided by 2 again to get 28. Continuing this process, we find that the prime factorization of 112 is 2^4 x 7. So, 112 can be expressed as 2^4 x 7.
Just 2.