No.
To check for divisibility by 9 add the digits together and if this sum is divisible by 9 then so is the original number. This can be repeated until a single digit remains which must be 9 for the original number to be divisible by 9.
For 98: 9 + 8 = 17 → 1 + 7 = 8 which is not 9, so 98 is not divisible by 9.
81: 8 + 1 = 9 which is divisible by 9, so 81 is divisible by 9 162: 1 + 6 + 2 = 9 which is divisible by 9, so 162 is divisible by 9 199: 1 + 9 + 9 = 19 → 1 + 9 = 10 → 1 + 0 = 1 which is not divisible by 9, so 199 is not divisible by 9. 1125: 1 + 1 + 2 + 5 = 9 which is divisible by 9, so 1125 is divisible by 9. So 199 is the only one not divisible by 9.
Yes, 441 is divisible by 9. To determine if a number is divisible by 9, you can add up its digits. In this case, 4 + 4 + 1 = 9, which is divisible by 9. Therefore, 441 is divisible by 9.
To determine if 235 is divisible by 9, we sum its digits: 2 + 3 + 5 = 10. Since 10 is not divisible by 9, 235 is not divisible by 9. In order for a number to be divisible by 9, the sum of its digits must be divisible by 9.
No, 998876 is not divisible by 9.
NO,532 is not divisible by 9.
No, but 98 is divisible by 298/2 = 49
Yes, and evenly too, with a quotient of 98 and zero remainder
No, but 98 is evenly divisible by 1, 2, 7, 14, 49, 98.
It is 882 becaise its digital sum equals 9 and so 882/9 = 98
No, it isn't. You can always check - by adding the digits together. If the resulting number is divisible by 3, then the original number is too. In this example - 9+8=17... 17 will NOT divide by three exactly therefore 98 won't either.
No. 98 is not evenly divisible by eight.
No. 98 is not evenly divisible by 21.
yes
2
yes
NO. 1110 is not divisible by 9. A number is divisible by 9 if the sum of its digits is divisible by 9. 1110 = 1 + 1 + 1 + 0 = 3 (3 is not divisible by 9, thus, 1110 is not divisible by 9.)
108 is divisible by 3.