C provides rectangular multidimensional arrays. In C, a two-dimensional array is really a one-dimensional array, each of whose elements is an array. An array is initialized by a list of initializations in braces; each row of a two-dimensional array is initialized by a corresponding sub-list. Example of two dimensional array initialization: char array_example[2][4] = { {11, 12, 13, 14}, {21, 22, 23, 24} };
Yes.
it depends how you have coded your program as: if you initialized your array (a) by loop from 0 then int lb=0,ub=n-1; //n is number of elements in array int mid=(lb+ub)/2; printf("middle number is :%d",a[mid]); if you initialized your array (a) by loop from 1 then int lb=1,ub=n; //n is number of elements in array int mid=(lb+ub)/2; printf("middle number is :%d",a[mid]);
int *ptr = (int *) calloc(10,sizeof(int));
It depends how the array is declared (fixed size or variable size) and where it is declared (global scope or local scope). If the array is declared in global scope (outside a function) and is fixed size, it will be allocated in static memory. If it is variable size, the pointer is stored in static memory while the array itself is allocated on the heap. The pointer in static memory points to the start address of the array in heap memory. If the array is declared in local scope (inside a function) and is fixed size, it will be allocated on the stack in whichever thread the function was called. If it is variable size, the local pointer is stored on the stack while the array is allocated on the heap. The pointer will fall from scope when the function returns so the array must not be allowed to outlive the function in which the pointer is declared. If the array must outlive the function that allocates the array, the pointer must be declared at a higher scope in the call stack and must be passed by reference to or returned by value from the function that allocates the array. If you provide your own memory manager, however, an array may be allocated wherever the memory manager's memory pool is allocated, be it in static memory, the stack or the heap. A memory manager essentially allocates an array of bytes which you can then utilise as you see fit (the array of bytes will be allocated as per the previous description for arrays in general).
Yes.
C provides rectangular multidimensional arrays. In C, a two-dimensional array is really a one-dimensional array, each of whose elements is an array. An array is initialized by a list of initializations in braces; each row of a two-dimensional array is initialized by a corresponding sub-list. Example of two dimensional array initialization: char array_example[2][4] = { {11, 12, 13, 14}, {21, 22, 23, 24} };
Yes.
it depends how you have coded your program as: if you initialized your array (a) by loop from 0 then int lb=0,ub=n-1; //n is number of elements in array int mid=(lb+ub)/2; printf("middle number is :%d",a[mid]); if you initialized your array (a) by loop from 1 then int lb=1,ub=n; //n is number of elements in array int mid=(lb+ub)/2; printf("middle number is :%d",a[mid]);
It declares an array of type double, it has size of 10, and all elements are initialized to 0;...int myArraySize = 10;double myArray[myArraySize] = {0.0}...
Uninitialized Page 59 Programming Logic and Design by Tony Gladdis
Uninitialized Page 59 Programming Logic and Design by Tony Gladdis
char myCharArray[10];
int *ptr = (int *) calloc(10,sizeof(int));
You cannot add elements to a fixed array in C or C++. If, however, the array is declared as a pointer to an array, you can add elements by allocating a new array, copying/adding elements as needed, reassigning the new array to the pointer, and deallocating the original array.
int sum = a + b; PS: a and b are int variables that must have been already declared and initialized.
During declaration, the declaration goes like this: extern <type> <variable-name> or <type> <function-name> (<parameter list>);