Steps to take:
Write the chemical formula : Al2O3
Calculate the number of moles for aluminum oxide. You should know the formula which is the mass given (0.051g) divided by the Mass of aluminum oxide.
Since there is '2' moles of Aluminium you multiplly the number of moles calculated for aluminum oxide by 2.
Then you have calculated the number of Ions.
24 mols of aluminum must have reacted since aluminum oxide is Al2O3
1,46 moles of aluminum fluoride contain 35,16848.10e23 atoms.
There are approximately 1.93 x 10^24 atoms in 3.20 moles of aluminum. This calculation is based on Avogadro's number, which states that 1 mole of any substance contains 6.022 x 10^23 particles (atoms, molecules, ions, etc.).
250 g iron (III) oxide is equal to 1,565 moles.
2 moles of Ca and 4 moles of OH
The formula for aluminum oxide is Al2O3, which means that, if aluminum oxide is ionically bonded, every formula mass of aluminum oxide contains three O-2 ions. In this instance, 0.65 formula masses of aluminum oxide would contain 3 X 0.65 or 1.95 moles of O2-. If aluminum oxide were covalently bonded, it would not contain any O-2 ions.
When aluminum oxide decomposes, it produces 2 moles of aluminum and 3 moles of oxygen for every mole of aluminum oxide. Therefore, for 26.5 moles of aluminum oxide decomposed, 3 * 26.5 = 79.5 moles of oxygen are produced.
There would be 4.38 moles of fluoride ions in 1.46 moles of aluminum fluoride, as the formula for aluminum fluoride is AlF3 with three fluoride ions per molecule of aluminum fluoride.
To determine the grams of aluminum oxide formed, we need to consider the balanced chemical equation for the reaction between aluminum and oxygen. The molar ratio between aluminum and aluminum oxide is 4:2. So, first calculate the moles of aluminum in 1020g, then use this to find the moles of aluminum oxide produced, and finally convert moles of aluminum oxide to grams.
If aluminum reacts completely with oxygen to form aluminum oxide, then 4.0 moles of aluminum will react to form 4.0 moles of aluminum oxide. Each mole of aluminum reacts with one mole of oxygen to form one mole of aluminum oxide.
When aluminum reacts completely with oxygen to form aluminum oxide, the molar ratio is 4:2. This means that 4 moles of Al produce 2 moles of Al2O3. So, if 5.23 moles of Al are reacted, half as many moles of Al2O3 can be made, which is 2.615 moles.
3.2 moles of water (H2O)
To determine the number of moles of aluminum oxide in 12.75g of aluminum oxide, you first need to find the molar mass of aluminum oxide, which is 101.96 g/mol. Then, divide the given mass (12.75g) by the molar mass to find the number of moles. So, 12.75g / 101.96 g/mol ≈ 0.125 moles of aluminum oxide.
To find the number of moles of chloride ions in aluminum chloride, you first need to convert 0.2520g of aluminum chloride to moles. Then, since there are three chloride ions per one aluminum chloride molecule, you would multiply the number of moles of aluminum chloride by 3 to find the moles of chloride ions.
In the reaction 4 moles of aluminum will react with 3 moles of oxygen to form 2 moles of aluminum oxide. Since we have 2.0 moles of aluminum, we would need (2.0 mol Al) x (3 mol O2 / 4 mol Al) = 1.5 moles of O2 to react with it.
Since the molar ratio between aluminum and aluminum oxide is 4:2, 8 moles of Al will produce 8/4 * 2 = 4 moles of Al2O3.
In one mole of aluminum III oxide (Al2O3), there are 2 moles of aluminum atoms (since there are 2 aluminum atoms in each formula unit of Al2O3) and 3 moles of oxygen atoms. Therefore, one mole of aluminum III oxide contains 2 + 3 = 5 moles of atoms. Avogadro's number (6.022 x 10^23) of atoms can be found in one mole of any substance.