If we have 150 nitrogen molecules, we would need an equal number of hydrogen molecules to react with them according to the balanced reaction equation for the formation of ammonia: N2 + 3H2 → 2NH3 Therefore, we would need 150 hydrogen molecules to react with 150 nitrogen molecules.
45 grams H20 x (1 mole H20/18 grams H2O) x (6.02E23 molecules H20/1 mole H2O) the grams H2O and moles H2O cancel out. When you punch it into your calculator, the answer comes out to: =1.505E24 molecules H2O
.150 M is the molarity of the solution, which is the number of moles per liter. So all you need to do is multiply the molarity by the number of liters. So .150 moles/liter x .550 L = .0825 moles
To find the number of moles of atoms in 150 g of sulfur, you need to first determine the molar mass of sulfur, which is about 32 g/mol. Then, you can use the formula moles = mass/molar mass. So, 150 g / 32 g/mol ≈ 4.69 moles of sulfur atoms.
To determine the number of moles in 150 grams of Al(OH)3, we first need to calculate the molar mass of Al(OH)3: Aluminum (Al) has a molar mass of 26.98 g/mol, oxygen (O) has a molar mass of 16.00 g/mol, and hydrogen (H) has a molar mass of 1.01 g/mol. Molar mass of Al(OH)3 = 26.98 + 3(16.00) + 3(1.01) = 78.03 g/mol Now, we can calculate the number of moles: Number of moles = Mass (g) / Molar mass Number of moles = 150 g / 78.03 g/mol ≈ 1.92 moles.
If we have 150 nitrogen molecules, we would need an equal number of hydrogen molecules to react with them according to the balanced reaction equation for the formation of ammonia: N2 + 3H2 → 2NH3 Therefore, we would need 150 hydrogen molecules to react with 150 nitrogen molecules.
45 grams H20 x (1 mole H20/18 grams H2O) x (6.02E23 molecules H20/1 mole H2O) the grams H2O and moles H2O cancel out. When you punch it into your calculator, the answer comes out to: =1.505E24 molecules H2O
To calculate the moles of NaOH used in the titration, multiply the volume (in liters) by the molarity. Converting 20.0 mL to liters (20.0 mL * 1 L/1000 mL = 0.020 L), the moles of NaOH used would be (0.020 L * 150 mol/L = 3.0 moles of NaOH).
To calculate the number of moles in 150 grams of NaCl, you need to know the molar mass of NaCl, which is approximately 58.44 g/mol. You can then divide the given mass (150 grams) by the molar mass to get the number of moles. In this case, 150 g / 58.44 g/mol ≈ 2.57 moles of NaCl.
To find the number of moles in 150 g of (NH4)2S, we first need to calculate the molar mass of (NH4)2S. The molar mass of (NH4)2S is 68.15 g/mol. Next, we use the formula: moles = mass / molar mass. Plugging in the values, we get moles = 150 g / 68.15 g/mol, which is approximately 2.20 moles of (NH4)2S.
150
.150 M is the molarity of the solution, which is the number of moles per liter. So all you need to do is multiply the molarity by the number of liters. So .150 moles/liter x .550 L = .0825 moles
This depends on many things including temperature, pressure, number of moles and molecular weight or the density
To find the number of moles of atoms in 150 g of sulfur, you need to first determine the molar mass of sulfur, which is about 32 g/mol. Then, you can use the formula moles = mass/molar mass. So, 150 g / 32 g/mol ≈ 4.69 moles of sulfur atoms.
No you need more copper
To determine the number of moles in 150 grams of Al(OH)3, we first need to calculate the molar mass of Al(OH)3: Aluminum (Al) has a molar mass of 26.98 g/mol, oxygen (O) has a molar mass of 16.00 g/mol, and hydrogen (H) has a molar mass of 1.01 g/mol. Molar mass of Al(OH)3 = 26.98 + 3(16.00) + 3(1.01) = 78.03 g/mol Now, we can calculate the number of moles: Number of moles = Mass (g) / Molar mass Number of moles = 150 g / 78.03 g/mol ≈ 1.92 moles.
To find the number of moles of ammonium sulfate in a 150g sample, you first need to calculate the molar mass of ammonium sulfate (NH4)2SO4, which is approximately 132.14 g/mol. Then, divide the given mass (150g) by the molar mass to get the number of moles, which would be approximately 1.14 moles.