To find the number of moles in 444 grams of magnesium chloride, you first need to calculate the molar mass of magnesium chloride. The molar mass of MgCl2 is about 95.21 g/mol. Next, calculate the number of moles by dividing the given mass by the molar mass: 444 g / 95.21 g/mol β 4.66 moles of magnesium chloride.
By stoichiometry, 2 moles of sodium carbonate will produce 2 moles of sodium chloride. The molar mass of sodium chloride is approximately 58.44 g/mol, so 2 moles would weigh about 116.88 grams.
To find the number of moles in 42.5 grams of sodium chloride (NaCl), you first need to calculate the molar mass of NaCl, which is 58.44 g/mol. Then divide the given mass by the molar mass to get the number of moles. In this case, 42.5 grams divided by 58.44 g/mol is approximately 0.727 moles of sodium chloride.
To convert moles to grams, you need to multiply the number of moles by the molar mass of the substance. The molar mass of sodium chloride (NaCl) is approximately 58.44 g/mol. Therefore, 4.40 moles of NaCl would be equal to 257.14 grams.
The molar mass of ammonium chloride (NH4Cl) is approximately 53.49 g/mol. To find the mass of 3 moles, multiply the molar mass by the number of moles: 3 moles x 53.49 g/mol = 160.47 grams of ammonium chloride.
To find the number of moles in 13.2 grams of magnesium, divide the mass of magnesium by its molar mass. The molar mass of magnesium is approximately 24.31 g/mol. So, 13.2 g / 24.31 g/mol β 0.54 moles of magnesium.
To determine the number of formula units in 2.5 grams of Magnesium Chloride, you first need to calculate the molar mass of the compound (MgCl2). Then, use this molar mass to convert the grams of Magnesium Chloride to moles. Finally, use Avogadro's number (6.022Γ10^23) to find the number of formula units in the given amount of Magnesium Chloride.
The molar mass of magnesium chloride MgCl2 is 95.21 g/mol. To find the mass of 6.80 moles, you would multiply the number of moles by the molar mass: 6.80 moles * 95.21 g/mol = 647.868 g. Therefore, the mass of 6.80 moles of MgCl2 is 647.868 grams.
1,11 moles of magnesium have 26,97855 g.
To find the number of grams of ammonium chloride in 0.500L of a 2.00M solution, we need to use the formula: concentration (M) = moles of solute / volume of solution (L). First, calculate the moles of ammonium chloride present in 0.500L of the solution using C = n/V. Then, convert moles to grams by multiplying by the molar mass of ammonium chloride (NH4Cl).
There are 0.13 moles in 20 grams of magnesium nitrate.
23.3772 grams are there in four tenths moles of sodium chloride
88,1 moles of magnesium is equivalent to 2 141,27 g.
To calculate the molarity, first determine the molar mass of magnesium chloride, which is 95.211 g/mol (24.305 g/mol for Mg and 35.453 g/mol for Cl). Next, calculate the number of moles of magnesium chloride in 128 grams by dividing the mass by the molar mass. Then, divide the moles by the volume of the solution in liters to get the molarity. So, the molarity of the solution would be about 1.34 M.
To calculate the molarity, you first need to find the moles of magnesium chloride using its molar mass. The molar mass of magnesium chloride is 95.21 g/mol. Next, use the formula Molarity = moles of solute / liters of solution to find the molarity. Convert 250 ml to liters (0.25 L) and then calculate the molarity.
To find the molarity of 48.6 grams of magnesium, you first need to determine the number of moles of magnesium in 48.6 grams using the molar mass of magnesium (24.305 g/mol). Then, you divide the moles of magnesium by the volume of the solution in liters to get the molarity.
The mass of 6.80 moles of magnesium chloride or MgCl2 is 647,435 g.
0,40 moles of sodium chloride contain 23,376 g.