All the numbers from 0 to 999 so 1000 numbers
However if you mean only using each number once the answer is about 720
* * * * *
No. The above answer refers to the number of permutations. Permutations are NOT the same as combinations as anyone who has studies any probability theory can tell you.
The number of combinations is 9C3 = 9*8*7/3*2*1 = 84
How many four digit combinations can be made from the number nine? Example, 1+1+2+5=9.
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
Just 1.
Any 5 from 59 = 5006386
If the same 7 digits are used for all the combinations then n! = 7! = 7*6*5*4*3*2*1 = 5040 combinations There are 9,999,999-1,000,000+1=9,000,000 7-digit numbers.
How many four digit combinations can be made from the number nine? Example, 1+1+2+5=9.
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
There are 5,461,512 such combinations.
It is: 9C7 = 36
10,000
15
6 ways: 931,913,139,193,391,319
There are 840 4-digit combinations without repeating any digit in the combinations.
I am assuming you mean 3-number combinations rather than 3 digit combinations. Otherwise you have to treat 21 as a 2-digit number and equate it to 1-and-2. There are 21C3 combinations = 21*20*19/(3*2*1) = 7980 combinations.
Just 1.
10C6 = 10*9*8*7/(4*3*2*1) = 210 combinations.
The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.