first you guess where the first switch could be, then the second switch is in the trash can below of the first switch.
t t t 1S t
t t t 2S t
t t t t t
t t t t t
t t t t t
1 answer
1 2 3 4
h h h h
h h h t
h h t h
h h t t
h t h h
h t h t
h t t h
h t t t
t h h h
t h h t
t h t h
t h t t
t t h h
t t h t
t t t h
t t t t
1 answer
import java.util.*;
import java.lang.String;
import java.io.*;
import java.util.Date;
import java.util.Timer;
class project
{
public static void main(String args[]) throws IOException
{
String sub1,sub2,sub3,sub4,sub5,sub6;
String name,sem;
int m1,m2,m3,m4,m5,m6,m7;
//Date dt = new Date(now.getTime()
int prn_no,seat_no,total;
float per;
float temp;
String msg="*";
long currentTimeInMillis = System.currentTimeMillis();
Date today = new Date( currentTimeInMillis );
Scanner in=new Scanner(System.in);
BufferedReader b=new BufferedReader(new InputStreamReader(System.in));
System.out.println("Enter name of student=");
name=b.readLine();
System.out.println("Enter prn number =");
prn_no=in.nextInt();
System.out.println("Enter name of semester=");
sem=b.readLine();
System.out.println("Enter Roll number =");
seat_no=in.nextInt();
System.out.println("Enter first subject name =");
sub1=b.readLine();
System.out.println("Enter marks =");
m1=in.nextInt();
System.out.println("Enter second subject name =");
sub2=b.readLine();
System.out.println("Enter marks =");
m2=in.nextInt();
System.out.println("Enter third subject name =");
sub3=b.readLine();
System.out.println("Enter marks =");
m3=in.nextInt();
System.out.println("Enter fourth subject name =");
sub4=b.readLine();
System.out.println("Enter marks =");
m4=in.nextInt();
System.out.println("Enter fifth subject name =");
sub5=b.readLine();
System.out.println("Enter marks =");
m5=in.nextInt();
System.out.println("\t\t\t\t\t\t DR.BABASAHEB AMBEDKAR MARATHWADA UNIVERSITY");
System.out.println("\t\t\t\t\t\t\tAurangabad-431004");
System.out.println("STUDENT NAME:"+name+"\t\t\tprn :"+prn_no+"\t\t\tSEAT NO:"+seat_no+"\t\t\tSEMESTER:"+sem);
System.out.println("------------------------------------------------------------------------------------");
System.out.println("\n\n| SUBJECTS"+"\t\t\t\t|\tMAXIMUM MARKS"+"\t|\t min marks"+"\t|\tOBTAINED MARKS");
System.out.println("------------------------------------------------------------------------------------");
if(m1>40)
msg="";
else
msg="*";
System.out.println("|"+sub1+"\t\t\t\t\t\t|\t100\t\t\t\t|\t40\t\t\t|\t"+m1);
if(m2>40)
msg="";
else
msg="*";
System.out.println("|"+sub2+"\t\t\t\t\t\t|\t100\t\t\t\t|\t40\t\t\t|\t"+m2);
//System.out.println(+sub2+"\t\t\t"+"|"+"\t\t100"+"\t\t\t"+"|"+"\t\t40"+"\t\t\t\t"+"|"+"\t\t"m2+msg+"\t|");
if(m3>40)
msg="";
else
msg="*";
System.out.println("|"+sub3+"\t\t\t\t\t\t|\t100\t\t\t\t|\t40\t\t\t|\t"+m3);
//System.out.println(+sub3+"\t\t\t"+"|"+"\t\t100"+"\t\t\t"+"|"+"\t\t40"+"\t\t\t\t"+"|"+"\t\t"m3+msg+"\t|");
if(m4>40)
msg="";
else
msg="*";
System.out.println("|"+sub4+"\t\t\t\t\t\t|\t100\t\t\t\t|\t40\t\t\t|\t"+m4);
//System.out.println(+sub4+"\t\t\t"+"|"+"\t\t100"+"\t\t\t"+"|"+"\t\t40"+"\t\t\t\t"+"|"+"\t\t"m4+msg+"\t|");
if(m5>40)
msg="";
else
msg="*";
System.out.println("|"+sub5+"\t\t\t\t\t\t|\t100\t\t\t\t|\t40\t\t\t|\t"+m5);
//System.out.println(+sub5+"\t\t\t"+"|"+"\t\t100"+"\t\t\t"+"|"+"\t\t40"+"\t\t\t\t"+"|"+"\t\t"m5+msg+"\t|");
System.out.println("------------------------------------------------------------------------------------");
total=m1+m2+m3+m4+m5;
System.out.println("\t\t\t\t\t\t\t\t\t\t\t\t\t"+"|"+"\t\t TOTAL ::"+total+"/500");
temp=(float)total/500;
per=temp*100;
System.out.println("\t\t\t\t\t\t\t\t\t\t\t\t\t"+"|"+"\t\t PERCENTAGE ::"+per+"%");
System.out.println("------------------------------------------------------------------------------------");
if(m1<40&&m2<40&&m3<40&&m4<40&&m5<40)
{
System.out.println("\t\t\t\t\t\t\t\t\t\t\t\t\t"+"|"+"\t\t RESULT ::DROPPED");
System.out.println("------------------------------------------------------------------------------------");
}
else if(m1<40&&m2<40m3<40&&m4<40&&m5<40)
{
System.out.println("\t\t\t\t\t\t\t\t\t\t\t\t\t"+"|"+"\t\t RESULT ::A.T.K.T.");
}
else if(per<35)
{
System.out.println("\t\t\t\t\t\t\t\t\t\t\t\t\t"+"|"+"\t\t RESULT ::FAILED");
}
else if(per>=35&&per<40)
{
System.out.println("\t\t\t\t\t\t\t\t\t\t\t\t\t"+"|"+"\t\t RESULT ::passed");
}
else if(per>=40&&per<59)
{
System.out.println("\t\t\t\t\t\t\t\t\t\t\t\t\t"+"|"+"\t\t RESULT :::passed with SECOND CLASS");
}
else if(per>=60&&per<75)
{
System.out.println("\t\t\t\t\t\t\t\t\t\t\t\t\t"+"|"+"\t\t RESULT :passed with first class");
}
else if(per>=75)
{
System.out.println("\t\t\t\t\t\t\t\t\t\t\t\t\t"+"|"+"\t\t RESULT :passed with DISTINCTION class");
}
System.out.println( today );
}
}
4 answers
What starts with "t" is filled with "t"and ends in "t"
2 answers
4 coins tossed could have the following patterns T T T T T T T H, T T H T, T H T T, H T T T T T H H, T H T H, T H H T, H H T T, H T H T, H T T H H H H T, H H T H, H T H H, T H H H H H H H Odds of 2H&2T = 6/16 = .375
1 answer
and t*t= t squared
you would only get t squared if you multiplied
2 answers
nobody because they thought it was a piece of
S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S S
H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H H
I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T
1 answer
cos(3t) = cos(2t + t) = cos(2t)*cos(t) - sin(2t)*sin(t)
= [cos2(t) - sin2(t)]*cos(t) - 2*cos(t)*sin(t)*sin(t)
= [cos2(t) - sin2(t)]*cos(t) - 2*cos(t)*sin2(t)
then, since sin2(t) = 1 - cos2(t)
= [2*cos2(t) - 1]*cos(t) - 2*cos(t)*[1 - cos2(t)]
= 2*cos3(t) - cos(t) - 2*cos(t) + 2*cos3(t)
= 4*cos3(t) - 3*cos(t)
1 answer
8: h-h-h, h-h-t, h-t-h, t-h-h, t-t-h, t-h-t, h-t-t and t-t-t.
2 answers
p > q
~q
Therefore, ~p
| p | q | p > q | ~q | ~p |
| t | t | t | f | f |
| t | f | t | t | f |
| f | t | t | f | t |
| f | f | t | t | t |
1 answer
2 answers
that
First, the correct question is, "What starts with T, ends with T and has T in it?"
Second, the correct answer is Teapot.
1 answer
All you have to do is make your font to "Wingdings" and press and hold the shift key and click "T" on your keyboard and you have a snowflake!!Then you can copy and paste it anywhere you want!!
T T T T T T T T
1 answer
All of the Tucker and Yoshi books are:
Tucker and Yoshi
T & Y 2
T & Y 3: Bowser's Revenge
T & Y 4
T & Y 5: Finding Mewtwo
T & Y 6
T & Y 7
T & Y 8
T & Y 9
T & Y 10
T & Y 11
T & Y 12: The Seven Demons
T & Y 13: Lucky 13
T & Y 14
T & Y 15
T & Y 16
T & Y 17
T & Y 18
T & Y 19
T & Y 20: The Gathering
T & Y 21
T & Y 22
T & Y 23
T & Y 24: The Dark Angel
T & Y 25
T & Y 26
T & Y 27: The Secret of Mew
T & Y 28
T & Y 29
T & Y: Saving Doomsday
T & Y 31
T & Y 32
T & Y 33
T & Y 34
T & Y 35
T & Y 36
T & Y 37
T & Y 37.5/ Meta-Knight's Side
T & Y: Future
T & Y 39
T & Y: Friend Or Foe?
T & Y 2.5
The Yoshi stories are:
Yoshi: Dead Space
Yoshi: Photosynthesis
Yoshi: Speed
Yoshi: Killed On One Condition
Yoshi: The End
1 answer
0.666
^^^^
his answer
mine
3 in 8 i believe. which is 0.375
you can get
h,h,h
h,t,h
h,t,t
h,h,t
t,h,h
t,t,h
t,h,t
t,t,t
the ones you are looking for are
h,h,t
t,h,h
h,t,h
1 answer
There are much more than three types of scales, but the 3 basic scales are the common major scale (T T S T T T S), the harmonic minor (T S T T S T1/2 S) and the melodic minor (T S T T T T S ascending - T S T T S T T descending). In brackets noticed I labelled the structure of the scale in tones and semitones.
T = tone
S = semitone
T1/2 = minor 3rd/augmented 2nd interval (3 semitones)
1 answer
The quotient of 6 and t is 6 over t, or 6 divided by t, depending on what t is. ( 6/t )
1 answer
There are 8 permutations of three coins ...
T T T
T T H
T H T
T H H
H T T
H T H
H H T
H H H
... counting heads and sorting by count, you get ...
0 - T T T
1 - T T H
1 - T H T
1 - H T T
2 - T H H
2 - H T H
2 - H H T
3 - H H H
... so, the probability of each possible number of heads is 0: 1 in 8, 1: 3 in 8, 2: 3 in 8, and 3: 1 in 8.
1 answer
it is true when at least one statement is true
p q p v q
t t t
t f t
f t t
f t f
You sure about this?
1 answer
(a - t)/(b - t) = c
=> a - t = c(b - t) = cb - ct = bc - tc
=> tc - t = bc - a
=> t(c - 1) = bc - a
=> t = (bc - a)/(c - 1)
1 answer
cos(t) - cos(t)*sin2(t) = cos(t)*[1 - sin2(t)]
But [1 - sin2(t)] = cos2(t)
So, the expression = cos(t)*cos2(t) = cos3(t)
1 answer
Use the formula a^2 - b^2 = (a -b)(a + b). So:
t^2 - (t - 1)^2
= [t - (t -1)][t + (t -1)] Now you can work and simplify the given expression.
=(t - t +1)(t + t -1)
=(1)(2t -1)
= 2t -1
1 answer
2t+8-t=-3
(t+t)+8-t=-3
-8 -8
(t+t)-t=-11
the -t and the +t cancel out
t=-11
2(-11)+8-(-11)=-3
-22+8+11=-3
1 answer
P Q (/P or /Q) T T F T F T F T T F F T
1 answer
It's GTTCATCCGA
1 answer
Words that start with T and end with T and have T exactly in the middle include tartest and tautest.
1 answer
T t s t t t s
1 answer
The curve given by (t-sinh(t)cosh(t), 2 cosh(t)), t real.
1 answer