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The nonsense strand of the given DNA sequence T-A-C-C-A-A-G-C-T-A-C-C-T-A-T-T-A-A-C-C-G is T-A-G-G-T-T-C-G-A-T-G-G-A-T-A-A-T-G-G-C. This sequence represents the complementary base pairs to the original sequence, following the A-T and G-C base pairing rule.

2 answers


The complementary DNA strand for the given sequence is A-T-G G-C-C T-A-C G-G-T C-T-A G-T-T T-A-G. Remember that A pairs with T and C pairs with G in DNA strands.

7 answers


24 different ways. wow that took a while

turkey- TU

cheese- C

lettuce- L

tomato- T

Tu, C, L, T

Tu, C, T L

Tu, L,C,T

Tu,L,T,C

Tu,C,T,L

Tu,C,L,T

C,TU,L,T

C,TU,T,L

C,L,TU,T

C,L,T,TU

C,T,L,TU

C,T,TU,L

L,TU,T,C

L,TU,C,T

L,C,TU,T

L,C,T,TU

L,T,TU,C

L,T,C,TU

T,TU,C,L

T,TU,L,C

T,L,TU,C

T,L,C,TU

T,C,TU,L

T,C,L,TU

2 answers



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Before we look at the complimentary mRNA sequence of the given DNA sequence, let us remember that RNA contains uracil (U) in place of Thiamine (T)

The querry sequence is:

t-a-c-c-t-c-g-c-a-a-c-t

So the mRNA sequence would be:

A U G G A G C G U U G A

9 answers


(a - t)/(b - t) = c

=> a - t = c(b - t) = cb - ct = bc - tc

=> tc - t = bc - a

=> t(c - 1) = bc - a

=> t = (bc - a)/(c - 1)

1 answer



B. G-G-A-T-G-C is the complement strand to C-C-A-T-C-G. The complementary base pairs are as follows: C-G, C-G, A-T, T-A, C-G, G-C.

7 answers


G-A-T-T-A-G-C-C-T-A-A-G-G-T-C-G


DNA base-pairing rules
Adenine - Thymine
Cytosine - Guanine


RNA base-pairing rules
Adenine - Uracil
Cytosine - Guanine

1 answer


The complementary DNA strand to the given sequence would be t c c g a g t c a g a t c g. This follows the base pairing rules where adenine pairs with thymine and guanine pairs with cytosine.

2 answers


The complementary DNA strand to "ttgccagc" is "aaggctcg". In complementary base pairing, thymine (T) pairs with adenine (A) and guanine (G) pairs with cytosine (C).

3 answers


To determine the complementary strand of DNA, you would match each base with its complementary base: T -> A, A -> T, G -> C, C -> G. So, the complementary strand to t-t-t-g-a-c-c-a-g would be a-a-a-c-t-g-g-t-c.

2 answers


The complementary strand for CGATTAC would be GCTAATG.

C and G are always paired together, and A and T are always paired together.

4 answers


The complementary strand to A-T-T-C-G-A-C-C-T-A-C-G would be T-A-A-G-C-T-G-G-A-T-G-C. This is because adenine pairs with thymine and cytosine pairs with guanine in DNA.

5 answers


the at atlantic

ocean

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Using the letters for Atlantic Ocean, some things you might see that are low to the ground include:

  • A - alligator
  • T - toad
  • L - lizard
  • A - armadillo
  • N - Nigeria
  • T - turtle
  • I - iris (flower)
  • C - cat

  • O - otter
  • C - cobra snake
  • E - eddy
  • A - ant
  • N - nut tree

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Unscramble the letters to form an English word:

C T T H C R A E I

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C pairs with G and A pairs with T. So, G G T C A T C A A. If that's not what you want, I'm sorry.

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It will be based on the process in which it involved- for replication, transcription or translation

As a rule the bases will be expressed in Capital letters

If it is replication the sequence will A-T-G-T-T-G-G-A-C as the components of DNA is Adenine,Guianine, cytosine and thymine

But if it is for transcription it will be A-U-G-U-U-G-G-A-C as in RNA thymine is replace by uracil

Sreekala.K.P

3 answers


The complementary strand to the given DNA sequence would be C T A G G T A C T C A A T G. This is because in DNA, adenine pairs with thymine and guanine pairs with cytosine.

3 answers



To show an insertion of a nucleotide (say "c") in the sequence "a-c-t-g-g-a-t", you would write it as "a-c-t-c-g-g-a-t". The inserted nucleotide "c" fits in between the existing nucleotides "t" and "g".

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In DNA, the complementary strand would be: GGATCAGTAC.

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A binds with T, G binds with C.

Therefore the complementary strand of ATG-CCC-TAT-AGC-GCG-CAA-AGA-G is:

TAC-GGG-ATA-TCG-CGC-GTT-TCT-C

2 answers


G-A-T-T-A-G-C-C-T-A-A-G-G-T-C-G


DNA base-pairing rules
Adenine - Thymine
Cytosine - Guanine


RNA base-pairing rules
Adenine - Uracil
Cytosine - Guanine

7 answers


G-A-T-T-A-G-C-C-T-A-A-G-G-T-C-G


DNA base-pairing rules
Adenine - Thymine
Cytosine - Guanine


RNA base-pairing rules
Adenine - Uracil
Cytosine - Guanine

1 answer


if weight of the feed, concentrate and tailing are F, C and T respectively and their corresponding assays f, c and t, then:

F=C+T

Ff=Cc+Tt

Ff=Cc+t(F-C)

therefore

F/C= (c-t)/(f-t) which is the ratio of concentration.

the plant recovery equals (Cc/Ff)*100

or based on the ratio of concentration the recovery is:

Recovery=100*((f-t)c)/((c-t)f)

1 answer


The complementary bases for the DNA strand aatggccttagcagttgcatga are taccggaaatcgtaacgtaact. In DNA, adenine pairs with thymine (A-T) and cytosine pairs with guanine (C-G).

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C- Control T- means test

Line under the C - Negative

Line under C and T- positive :)

1 answer


Find I = ∫ tan³ x dx. The solution is: I = ½ tan² x - log cos x. * * * Here is how we can obtain this result: First, let t = tan x, s = sin x, and c = cos x; then, dI = t³ dx, ds = c dx, dc = -s dx, and dt = (1 + t²) dx; and, of course, t = s / c. By algebra, t³ = t(t² + 1) - t; thus, we have dI = t³ dx = t(t² + 1) dx - t dx = t dt - t dx. Now, d (t²) = 2t dt; thus, t dt = ½ d(t²). On the other hand, we have d log c = dc / c = -s dx / c = -t dx; thus, t dx = -d log c. Combining these results, we have dI = t dt - t dx = ½ d(t²) - d log c. This integrates readily, giving I = ½ t² - log c, which is the solution we sought. * * * We may check our result, by differentiating back: dt / dx = 1 + t²; and d(t²) / dt = 2t; thus, (d/dx)(t²) = 2t dt / dx = 2t (1 + t²). Also, we have d log c / dc = 1 / c; and dc / dx = -s; whence, (d/dx)(log c) = (dc / dx) / c = -s / c = -t. Then, dI / dx = ½ (d/dx)(t²) - (d/dx)(log c) = t (1 + t²) - t = t + t³ - t = t³, re-assuring us that we have integrated correctly.

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it means


10 C R of a T :)

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A to T, T to A, G to C, C to G

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C. T. Onyekwelu was born in 1898.

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T. C. Chao died in 1979.

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C. T. Fernando died in 1977.

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C. T. Fernando was born in 1921.

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C. T. Bate was born in 1823.

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C. T. Bate died in 1889.

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T. C. Murray died in 1959.

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T. C. Murray was born in 1873.

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T. C. Hsu died in 2003.

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T. C. Hsu was born in 1917.

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T. C. Worsley died in 1977.

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T. C. Worsley was born in 1907.

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T C Narendran was born in 1944.

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T. C. Hammond died in 1961.

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T. C. Hammond was born in 1877.

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T in C = ( T in F - 32.0 ) ( 5/9 )

T in C = ( 15 - 32.0 ) ( 5/9 ) = -9.4 C <-----------------

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