intrepidity

(2+2)/(2+2)=1

(2/2)+(2/2)=2

(2*2)-(2/2)=3

(2+2+2)-2=4

(2+2)+(2/2)=5

(2*2*2)-2=6

((2-.2)/.2)+2=7

2+2+2+2=8

(22/2)+2=9

((2+2)*2)+2=10

((2-.2)/.2)+2=11

(2+2+2)*2+=12

(22/2)+2=13

(2/.2)+(2+2)=14

2+(2/2)/.2=15

(2+2)*(2+2)=16

...??????????=17

((2+2)/.2)-2=18

((2+2)-.2)/.2=19

22- √(2+2)=20

230.
2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2 = 1073741824

21

As a fraction it is: 2/9

256

2, 128

2, 2, 64

2, 2, 2, 32

2, 2, 2, 2, 16

2, 2, 2, 2, 2, 8

2, 2, 2, 2, 2, 2, 4

2, 2, 2, 2, 2, 2, 2, 2

8192

32

2+2+2+2+2+2+2+2+2+2+2+2+(2x0)

=2+2+2+2+2+2+2+2+2+2+2+2+0

=24

2+2+2=6

2 * 2 * 2 * 2 * 2 * 2 * 2, or 27.

Broken down as follows.....

128

2, 64

2, 2, 32

2, 2, 2, 16

2, 2, 2, 2, 8

2, 2, 2, 2, 2, 4

2, 2, 2, 2, 2, 2, 2

128

2*64

2*2*32

2*2*2*16

2*2*2*2*8

2*2*2*2*2*4

2*2*2*2*2*2*2

2^7

2 + 2 - 2 = 2 or 2+(2-2)=2+0=2

128

2, 64

2, 2, 32

2, 2, 2, 16

2, 2, 2, 2, 8

2, 2, 2, 2, 2, 4

2, 2, 2, 2, 2, 2, 2

2 + 23 = 25

3 + 3 + 19 = 25

3 + 5 + 17 = 25

3 + 11 + 11 = 25

5 + 7 + 13 = 25

7 + 7 + 11 = 25

2 + 2 + 2 + 19 = 25

2 + 2 + 2 + 2 + 17 = 25

2 + 2 + 2 + 2 + 2 + 2 + 13 = 25

2 + 2 + 2 + 2 + 2 + 2 + 2 + 11 = 25

2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 7 = 25

2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 5 = 25

2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 3 = 25

800

2, 400

2, 2, 200

2, 2, 2, 100

2, 2, 2, 2, 50

2, 2, 2, 2, 2, 25

2, 2, 2, 2, 2, 5, 5

480

2, 240

2, 2, 120

2, 2, 2, 60

2, 2, 2, 2, 30

2, 2, 2, 2, 2, 15

2, 2, 2, 2, 2, 3, 5

2+2+2+2+2+2+2+2+2+2+2+2

Its 4 ;p

40

-1+(2x9)=17

1 and 9 are not twos.

How about this: (2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2) /2 = 17

They are opposite parallel lines with points of (-2, 2) (2, 2) and (-2, -2) (2, -2)

210 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 =1,024
1024

LCM factoring

512=2*2*2*2*2*2*2*2*2

648=2*2*2*2*3*3*3*3

lcm=2*2*2*2*2*2*2*2*2*3*3*3*3=41,472

The answer is 0 because at the end it is multiplied by 0

The expression "2-2-2-2-2-2-2-2-2-2-2-2-2-2-2-2-2-2-2-3333333333333333333333333" consists of multiple subtractions of 2 followed by a long string of 3's. The repeated subtraction of 2 results in a negative number, specifically -36 (as there are 18 instances of 2), and the long string of 3's remains as is. Therefore, the expression simplifies to -36 followed by 3333333333333333333333333, but since they are not directly combined mathematically, the final result is more symbolic than numerical.

Negative numbers do not have prime factorizations.

2

you can break 800 in

2*2*2*2*2*5*5 = 2^5 * 5^2

so its divisible by any combination of multiplying numbers 2,2,2,2,2,5,5 where you can you only one in each combo.

so:

1

2

2*2=4

2*2*2=8

2*2*2*2=16

2*2*2*2*2=32

2*5=10

2*2*5=20

2*2*2*5=40

2*2*2*2*5=80

2*2*2*2*2*5=160

2*5*5=50

2*2*5*5=100

2*2*2*5*5=200

2*2*2*2*5*5=400

2*2*2*2*2*5*5=800

5

5*5=25

192

2, 96

2, 2, 48

2, 2, 2, 24

2, 2, 2, 2, 12

2, 2, 2, 2, 2, 6

2, 2, 2, 2, 2, 2, 3

2

Gcf

32=2*2*2*2*2

56=2*2*2*7

64=2*2*2*2*2*2

gcf=2*2*2 =8

2*2*2*2*2*2*2*2*2*2=1024

2^10 = 1024

1/2 + (11/2)*2 = 1/2 + (3/2)*2 = 1/2 + 3 = 31/2

1/2 + (11/2)*2 = 1/2 + (3/2)*2 = 1/2 + 3 = 31/2

1/2 + (11/2)*2 = 1/2 + (3/2)*2 = 1/2 + 3 = 31/2

1/2 + (11/2)*2 = 1/2 + (3/2)*2 = 1/2 + 3 = 31/2

2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 * 23 = 23552

2*2*2*2*2*2*2*2*2*3

1,000,000

1,000, 1,000

2, 500, 2, 500

2, 2, 250, 2, 2, 250

2, 2, 2, 125, 2, 2, 2, 125

2, 2, 2, 5, 25, 2, 2, 2, 5, 25

2, 2, 2, 5, 5, 5, 2, 2, 2, 5, 5, 5

Listed in order ...2, 2, 2, 2, 2, 2, 5, 5, 5, 5, 5, 5

By multiplication

21 = 2

22 = 2 x 2 = 4

23 = 2 x 2 x 2 = 8

24 = 2 x 2 x 2 x 2 = 16

25 = 2 x 2 x 2 x 2 x 2 = 32

26 = 2 x 2 x 2 x 2 x 2 x 2 = 64

27 = 2 x 2 x 2 x 2 x 2 x 2 x 2 = 128

28 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 = 256

29 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 = 516

It is: (2+2+2)*2 = 12

(2/2) times (2/2)

(2/2) divided by (2/2)

22 divided by 22

(2 + 2) / (2 + 2)

96

2, 48

2, 2, 24

2, 2, 2, 12

2, 2, 2, 2, 6

2, 2, 2, 2, 2, 3

400

200, 2

100, 2, 2

50, 2, 2, 2

25, 2, 2, 2, 2

5, 5, 2, 2, 2, 2

I'm not sure if you're allowed to do this, but here goes

Factor the !@#$ out of EVERYTHING

2, 2, 2, 2, 2, 2, 2, 2, 2, 2

Cool, alright, let's get it on.

(((2*2*2*2)+2+2+2+(2/2))-2

16+6+1-2

16+7-2

23-2

21

The prime factors are 2, 2, 2, 2, 2, 2, 47

Others are combinations of the primes, i.e.

2 x 2 = 4

2 x 2 x 2 = 8

2 x 2 x 2 x 2 = 16

2 x 2 x 2 x 2 x 2 = 32

2 x 2 x 2 x 2 x 2 x 2 = 64

2 x 47 = 94

2 x 2 x 47 = 188

2 x 2 x 2 x 47 = 376

2 x 2 x 2 x 2 x 47 = 752

2 x 2 x 2 x 2 x 2 x 47 = 1504