here is it
s s s s * - S P ( - P O [%P] P O s Y i 4 - s s s s s s s * S P ( - P O [%P] P P s O [4o] i - * * * * ( ( ( ( % % % % 4 4 4 4 - s s s s * - S P ( - P O [%P] P O P P s O [4o] i - s s s s s * - S P ( - O O s P O O s P O O g g g g g * - s D ( - D D [%D] D D S - [4s] s s s s s s s s* - S P ( - O O s P O O s P O O - O g g g D g D ( - P s S - [%D] D D s D s 4 - i o O - g g g D g D ( - P s S S D s D D s D s 4 i o O - g g g D g h ( H h - D D D D S S s - s s s s * - S P ( - O P O o o s o O 4
Share this:1 answer
s = p^2 - 5
*also, p = sqrt (s+5)
2 answers
Among s-s,s-p,p-p
sigma P-P is strong enough because of greater overlapping.The bond strengths for sigma S-S is 1.0 ,for sigma S-P is 1.71 and for sigma P-P is 3.0. so sigma
P-P is stronger it means that it is more stable. But many books they have given that s-s overlapping is more than p-p overlapping .This is not true because due spherical shape of the s orbital the charge is symmetrically distributed and also small size there will not effective overlapping of orbitals as P-P overlapping .So P-P bond is stronger than S-S bond.
2 answers
P in the S S = Planets in the Solar System.
1 answer
All s is p ---->Let this be premise 1 conversion of this premise is: Some p is s.
derivation of this premise is: some s is p.
All p is k ------>Let this be premise 2
conversion of this premise is: Some k is p.
derivation of this premise is: some p is k.
Conclusion of premise 1 and premise 2:
All s is p
All p is k
Conclusion: All s is k
5 examples:
i) some k is o
some o is t
valid conclusions: I) some k is t
II) some t is k
III)some o is k
IV)some t is o
ii) No s is p
No p is k
Valid conclusions: I) No p is s
II)No k is p
III)some s is not p
IV)some p is not k
V)some p is not s
VI)some k is not p
iii)All s is p
All p is k
Valid conclusions: I)All s is k
II)some s is p
III)some p is k
IV)some s is k
V)some p is s
VI)some k is p
VII)some k is s
vi)some s is not p
some p is not k
Valid conclusions: I) No valid conclusion
vi)All s is p
some p is k
valid conclusions: I)some s is k
II)some s is p
III)some k is p
VI)some k is s
V)some p is s
2 answers
If p = 2s + 5, then s = (p-5)/2
or 1/2 (p-5)
---
p = 2s +5
p-5 = 2s
(p-5)/2 = s
1 answer
Energy Level: Sublevels
1: s
2: s, p
3: s, p, d
4: s, p, d, f
5: s, p, d, f, g
6: s, p, d, f, g, h
7: s, p, d, f, g, h, i
1 answer
If the question refers to "Mississippi", there is a short song that explains this : (two double S and a double P) M I S
S I S
S I P P I
That used to be so hard to spell
It used to make me cry
But since I've studied spelling
It's just like pumpkin pie:
M I S
S I S
S I P P I.
1 answer
char *strdup (const char *s)
{
size_t len;
char *p;
if ( !s )
return NULL;
len = strlen (s);
p = malloc (len+1);
if (p && len)
{
memcpy (p, s, len);
p[len] = '\0';
}
return p;
}
1 answer
E-S-P- - 1958 Tales of E-S-P- 1-5 was released on:
USA: 8 August 1958
2 answers
The outermost s sublevel of the representative elements is filled first, followed by the p sublevel. This results in the outermost electron configuration being in the s and p sublevels.
2 answers
E-S-P- - 1958 Tales of E-S-P- 1-4 was released on:
USA: 1 August 1958
1 answer
E-S-P- - 1958 Tales of E-S-P- 1-6 was released on:
USA: 15 August 1958
1 answer
the s means standard and the p is poor. the s and p 500 was to see who had a standard amount of something, the poor people could not use this.
1 answer
19999555
1 answer
What calloc does is:
void *calloc (size_t s1, size_t s2)
{
size_t s= s1*s2;
void *p= malloc (s);
if (p && s) memset (p, 0, s);
return p;
}
1 answer
M-i-s-s-i-s-s-i-p-p-i (without the hyphens of course). Be sure to always capitalize the "m".
1 answer
P. S. Josh has written:
'Josh PS' -- subject(s): Exhibitions
1 answer
P. S. Lavarack has written:
'Dendrobium and its relatives' -- subject(s): Dendrobium
1 answer