K-6 could mean school grades kindergarten to 6th grade. It can also refer to a mountain in Pakistan which has been an attraction for mountain climbing.
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is multiplication , so you multiply like k(9)=36 then k would equal k=4 because you divide 9 by 36 and it equals =4
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4x-9=k
4x=k+9
Divide by 4 to isolate the x
x=(1/4)k+(9/4)
x=1/4 k+ 9/4
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There is no such thing as a k-6 because k-9 actually means canine.
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Nothing is a K-6. K-9 is only used as an abbreviation for canine.
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Nothing. The term "K-9" originated in the military, and is just a contraction of the word "canine."
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Nothing. The term "K-9" originated in the military, and is just a contraction of the word "canine."
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"K-9" is a bastardization of "Canine". K-9 units usually consist of a Handler or dog trainer and a police dog.
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It is because 3 is a factor of 9.
So if 9 is a factor of some number X, then X = k*9 for the factor pair 9 and k
But X = k*9 = k*(3*3) = (k*3)*3 so that X is k*3 times 3 ie it is a multiple of 3.
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Only if all the suits are the same for the 9 10 Q Q K combo and all the suits are not the same on the 9 9 8 8 K combo - in that case, you'd have a straight. Otherwise, no - 9 10 Q Q K is only one pair, whereas 9 9 8 8 K is two pair.
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k2 + 3k =108
k2 + 3k - 108 = 0
(k - 9) (k + 12)
k = -9 , k = 12
ANSWER:
k = -9 , k = 12
I hope this helps!
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"Than" changes the order of the sentence and "of" implies paratheses.
(17-k)+9
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k/9-3=9
k/9=9+3
k/9=12
k=12*9
k=108
now lets check our answer where k=108
k/9-3=9
108/9-3=9
12-3=9
9=9
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If you want to say "Nine is less than a number k," you would write 9<K. If you're asking for an equation, e.g. "Nine less than a number k is equal to that number divided by three," you would write k - 9.
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It is a fraction of the form (8*k)/(9*k) where k is any non-zero integer.
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No, bears are not in the K-9 family. The K-9 family typically refers to domestic dogs, while bears belong to the Ursidae family.
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(k+3)/8 = 5/9
Cross Multiply:
9(k+3) = 5*8
Distribute:
9k+27 = 40
Subtract 27 from each side:
9k = 13
Divide each side by 9:
k = 13/9
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The probability is 1. And the same is true for any other digit.
This counter-intuitive result can be proved as follows:
Ignore numbers with leading zeros.
There are 9 1-digit numbers of which 8 do not contain any 2s;
There are 90 2-digit numbers of which 8*9 do not contain any 2s;
There are 900 3-digit numbers of which 8*9*9 do not contain any 2s;
and so on.
The total number of k digit numbers is 9 + 90 + 900 + ... + 9*10^(k-1)
= 9*[10^k-1]/[10 - 1] = 10^k - 1
Of these, the count of numbers which do not contain any 2s = 8 + 8*9 + 8*9^2 + ... + 8*9^(k-1)
= 8*[9^k-1]/[9 - 1] = 9^k - 1
So the probability that the numbers do not contain any 2s is [9^k - 1]/[10^k - 1] which, as k gets larger, approaches 9^k/10^k = (0.9)^k which tends to 0.
So, the probability that the number DOES contain at least one 2 = 1 - Pr(It contains none) = 1 - 0 = 1.
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It is any member of the set of fractions of the form (9*k)/(20*k) where k is a non-zero integer.
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It is any member of the set of fractions of the form (6*k)/(9*k) where k is a non-zero integer.
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K-6 refers to Kindergarten through 6 grade, commonly considered to be elementary school
k-9 refers to a trained Police Dog
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9 is an integer, not a fraction. There is not really a sensible way of writing it as a fraction. However, if you must, you can use (9*k)/k where k is any non-zero integer as an equivalent fraction.
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Any element of the set of numbers of the form 126*k, where k is an integer, is evenly divisible.
126*k = 9*(14*k)
126*k = 6*(21*k)
126*k = 7*(18*k)
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First rearrange the second equation to fit the form y = mx + c, where m = slope
We get y = (9/k) x - 7/k
Parallel lines have the same slope. From equation 1, slope = k
From equation 2, slope = 9/k . Equating the two slopes we get k = 9/k; k² = 9; k = 3
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K = (°F + 459.67) × 5/9 K = (10,000 + 459.67) * 5/9 = 5,810.93
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K-9 - 1991 TV was released on:
USA: 6 July 1991
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Detective K-9 - 1926 was released on:
USA: 1 July 1926
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There are infinitely many of them and so it is not possible to list them. They are numbers of the form 9*k where k is an integer.
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Kelvins = 5/9(F-32) + 273.15
K = 5/9(780-32) + 273.15
K = 5/9(748) + 273.15
K = 415.55 + 273.145 = 688.71
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9 - 2k - 3 = k
Add 2k to both sides: 9 - 3 = k + 2k
Combine like terms: 6 = 3k
Divide both sides by 3: 2 = k
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The solutions are:x = 11 + k*120
x = 51 + k*120
x = 87 + k*120
where k is an integer.
In the interval (0, 360) there are 9 solutions.
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