Marty Higginbotham was born in April 1963, in Birmingham, Alabama, USA.
1 answer
Irene Higginbotham was born on June 11, 1918, in Worcester, Massachusetts, USA.
1 answer
Charles T. Higginbotham has written:
'Jeweled bearings for watches'
1 answer
The phone number of the Higginbotham House Museum is: 276-988-3800.
2 answers
Aloyisus Leon Higginbotham Jr. was born on February 2, 1928.
1 answer
for (i=0; i<IMAX; i++) for (j=0; j<JMAX; j++) c[i,j] = a[i,j] + b[i,j];
1 answer
Aloyisus Leon Higginbotham Jr. was born on February 2, 1928.
1 answer
John Higginbotham has written:
'Kington Camp' -- subject(s): History, Kington Camp
1 answer
Irv Higginbotham died June 12, 1959, in Seattle, WA, USA.
1 answer
Irv Higginbotham was born April 26, 1882, in Homer, NE, USA.
1 answer
Obviously there is more than one way to do this.
VL = Ldi/dt Volts has units of Joules/Coulomb: J/C i has units of Coulombs/second: C/s
So di/di is C/s^2 L has units of J/C / C/s^2 = Js^2/C^2
Ic = CdV/dt => Ic/dV/dt = C/s / J/C-s = C/s * C-s/J = C^2/J C has units of C^2/J OR you could just type Q = CV => C = Q/V = C/J/C = C^2/J same answer
R = V/I => J/C / C/s = J-s/C^2
2 answers
#include<stdio.h>
#include<conio.h>
void main()
{
clrscr();
int i,j,m,a[20],b[20],c[20],max;
printf("enter no of elements");
scanf("%d",&m);
printf("enter elements");
for(i=0;i<=m;i++)
{
scanf("%d",&a[i]);
}
max=a[i];
for(i=0;i<=m;i++)
{
if(max<a[i])
{
max=a[i];
}
}
for(i=0;i<=max;i++)
{
c[i]=0;
}
for(j=0;j<=m;j++)
{
c[a[j]]=c[a[j]]+1;
}
for(i=0;i<=max;i++)
{
c[i]=c[i]+c[i-1];
}
for(j=m;j>=1;j--)
{
b[c[a[j]]]=a[j];
c[a[j]]=c[a[j]]-1;
}
printf("AFTER SORTING");
for(i=0;i<=m;i++)
{
printf("%d",b[i]);
}
getch();
}
1 answer
The address of the Higginbotham House Museum is: Pisgah Rd, Tazewell, VA 24651
1 answer
Aloyisus Leon Higginbotham Jr. died on December 14, 1998 at the age of 70.
1 answer
J. C. C Church has written:
'Mining research review'
1 answer