I am a member of the [HLM] clan. [HLM] is an invite only clan. You have to be noticed by [HLM], you can't just go there an request membership. Unlike most clans, even the recruiting website is a secret, closed group. [HLM] is a warring clan. You will need to have strong A/D to join. Players who focus on energy are not too highly sought after regardless of their level. Most [HLM] members fight 30-200 levels up in wars. Some [HLM] members defected from losing clans in a war because they impressed [HLM] with their fighting ability and were asked to join. [HLM] is also a very small clan compared to others. Where most well known clans will typically have 6,000-10,000 members on their recruiting site alone [HLM] is around 1,000 strong. Despite small numbers [HLM] has held its own against up to 10 clans at once before. [HLM] is far from the strongest clan in MW but is probably the strongest clan of it's size, and stronger than most clans 10 x our size. [HLM] is also a very suspicious clan. If you contact an [HLM] member and start asking about joining most of us will wonder if you really want to join or are just doing recon for a rival clan. Only about 20% of [HLM] members are allowed access to the off FB website. Even after joining you must "prove yourself worthy" of "next level" membership. This requires far more than just adding the [HLM] tag. Long story short: You can't find the [HLM] recruiting site. We will find you.

The airport code for Park Township Airport is HLM.

The symbol for Hillman Group Capital Trust in the AMEX is: HLM^.

Marie-Sissi Labreche has written:

'Lune dans un HLM'

Tourist attractions in Dakar include the Dakar Grand Mosque, the Dakar Cathedral, the IFAN Museum of West African culture, the African Renaissance Monument, Senegal Zoo in Hann Park, the historic Goree Island, and various markets, including Marche Sandaga and Marche HLM. Dakar also contains the University of Dakar.

Nassim Boutelis has: Played Karim in "Le traitre" in 2007. Played Idriss in "Histoires de vies" in 2009. Played Idriss in "Clandestin" in 2010. Played Adolescents HLM in "La ligne droite" in 2011. Played Abdel - le 1er commis in "Les saveurs du Palais" in 2012.

The Amur Leopard is an predator so occasionally it doesnt have a predator , larger animals may eat amur leopard cubs but other than that amur leopards are predators not prey

(5/5)*(5/5)=1

(5/5)+(5/5)=2

(5+5+5)/5=3

sqrt(5+5)-(5/5)=4

sqrt(5+5)*(5/5)=5

sqrt(5+5)+(5/5)=6

5+((5/5)/5)=7

5+.5+(5*.5)=8

(5+5)-(5/5)=9

sqrt(5+5)+sqrt(5+5)=10

5+5+(5/5)=11

(5*5*.5)-.5=12

(5*5*.5)+.5=13

((5!/5)*.5)+5=17 (5!/5)*sqrt(5*5)=19

5*5-sqrt(5*5)=20 (55/5)/.5=22

(5!/5)-(5/5)=23

(5!/5)-(5-5)=24

(5!/5)+(5/5)=25

(5*5)+(5/5)=26

(55*.5)-.5=27

(55*.5)+.5=28

(5!/5)+sqrt(5*5)=29

5*5+sqrt(5*5)=30

1 = (5 - 5)*5 + 5/52 = [(5+5)/5]*(5/5)3 = (5+5)/5 + 5/54 = (5+5+5+5)/55 = (5/5)*(5/5)*56 = (5*5)/5 + 5/57 = (5*5 + 5 + 5)/58 = (5+5+5)/5 + 59 = (5*5 - 5)/5 + 510 = (5*5 + 5*5)/5

25 different ways:

20, 20, 20, 20, 5

20, 20, 20, 10, 10, 5

20, 20, 20, 10, 5, 5, 5

20, 20, 20, 5, 5, 5, 5, 5

20, 20, 10, 10, 10, 10, 5

20, 20, 10, 10, 10, 5, 5, 5

20, 20, 10, 10, 5, 5, 5, 5, 5

20, 20, 10, 5, 5, 5, 5, 5, 5, 5

20, 20, 5, 5, 5, 5, 5, 5, 5, 5, 5

20, 10, 10, 10, 10, 10, 10, 5

20, 10, 10, 10, 10, 10, 5, 5, 5

20, 10, 10, 10, 10, 5, 5, 5, 5, 5

20, 10, 10, 10, 5, 5, 5, 5, 5, 5, 5

20, 10, 10, 5, 5, 5, 5, 5, 5, 5, 5, 5

20, 10, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5

20, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5

10, 10, 10, 10, 10, 10, 10, 10, 5

10, 10, 10, 10, 10, 10, 10, 5, 5, 5

10, 10, 10, 10, 10, 10, 5, 5, 5, 5, 5

10, 10, 10, 10, 10, 5, 5, 5, 5, 5, 5, 5

10, 10, 10, 10, 5, 5, 5, 5, 5, 5, 5, 5, 5

10, 10, 10, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5

10, 10, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5

10, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5

5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5

6

1+8+5+4+5+5-5-5-5-5-5-5-5-5-5 = -17

50 50

25 25 25 25

20 x .05

50 25 25

50 25 5 5 5 5 5

50 5 5 5 5 5 5 5 5 5 5

25 25 25 5 5 5 5 5

25 25 5 5 5 5 5 5 5 5 5 5

25 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5

0: (5x5)-(5x5)

1: (5:5)+5-5

2: (5:5)+(5:5)

3: (5+5+5):5

4: [(5x5)-5]:5

5: [(5-5)x5]+5

6: [(5x5)+5]:5

7: [(5+5):5]+5

10: 5+5+5-5

11: (5:5)+5+5

15: (5x5)-5-5

20: 5+5+5+5

24: (5x5)-(5:5)

25: (5x5)+5-5

26: (5x5)+(5:5)

30: [(5:5)+5]x5

35: (5x5)+5+5

45: [(5+5)x5]-5

50: (5x5)+(5x5)

55: [(5+5)x5]+5

75: (5+5+5)x5

120: (5x5x5)-5

130: (5x5x5)+5

625: 5x5x5x5

This really di'tkhjbvrc2j d2c lddsnkekjmcvk db v3bjcebrublixwniwdjjcjdcd c fd dfvfgnjrf

1953125

5+5-5+5-5+5-5+5-5

0: (5x5)-(5x5)

1: (5:5)+5-5

2: (5:5)+(5:5)

3: (5+5+5):5

4: [(5x5)-5]:5

5: [(5-5)x5]+5

6: [(5x5)+5]:5

7: [(5+5):5]+5

10: 5+5+5-5

11: (5:5)+5+5

15: (5x5)-5-5

20: 5+5+5+5

24: (5x5)-(5:5)

25: (5x5)+5-5

26: (5x5)+(5:5)

30: [(5:5)+5]x5

35: (5x5)+5+5

45: [(5+5)x5]-5

50: (5x5)+(5x5)

55: [(5+5)x5]+5

75: (5+5+5)x5

120: (5x5x5)-5

130: (5x5x5)+5

625: 5x5x5x5

A.

5+5-5=

10-5=

5

..... ..... ..... ..... ..... ..... ..... ..... ..... ..... ..... .....

B.

5+5-5=

5+0=

5

..... ..... ..... ..... ..... ..... ..... ..... ..... ..... ..... .....

C.

5+5-5=

-5+5+5=

-5+10=

5

The trick here is to multiply by the value 1, but express it as (5 - √5)/(5 - √5). This forms a difference of squares on the bottom, eliminating the radical:

(1 + √5) / (5 + √5)
= (1 + √5)(5 - √5) / (5 + √5)(5 - √5)
= (5 - √5 + 5√5 - 5) / (25 - 5√5 + 5√5 - 5)
= 4√5 / 20
= √5 / 5

5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 = 55

5 + 5 + 5 - 5 + 5 + 5 - 5 + (5 x 0) = 15

5 + 5 + 5 + 5 + 5 + 5 = 30

Note that the reason there exists a technique called multiplication is so that we do not have to perform tedious and lengthy series of addition such as the one you have presented. So, you have given us 24 of the number 5 to add. 24 x 5 = 120.

(Addition form)

5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 = 120

((((5*5)/5)*(((5/5)*5))-5)-5+5)*5

(5 * 5) - ((5/5)5) = 25 - 1 = 24.

I. I. I. I. I i i. I. I. I i. I. I. I. I i. I. I. I. I i. I. I. I. I 5. 5. 5. 5. 5 5+5+5+5+5=25 a. 25

9*5=45 or 5+5+5+5+5+5+5+5+5=45 or1*5*9=45

5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 = 45, the shorter version is 5*9.

For a positive integer value n, "to the power of" n means the number multiplied by itself n times. "To the power of n" is also defined for negative, rational, irrational and complex n, but all that is not required now.

So 5 to the power of 9 is 5*5*5*5*5*5*5*5*5 [that is, 9 lots of 5]. This is normally written as 59

So 59 = 5*5*5*5*5*5*5*5*5 = 25*5*5*5*5*5*5*5 = 125*5*5*5*5*5*5 = 625*5*5*5*5*5 = 3125*5*5*5*5 = 15625*5*5*5 = 78125*5*5 = 390625*5 and that is 1953125.

20 different ways

____________________________________________________________

There are 12 different ways -

20+20+10

20+20+5+5

20+10+10+10

20+10+10+5+5

20+10+5+5+5+5

20+5+5+5+5+5+5

10+10+10+10+10

10+10+10+10+5+5

10+10+10+5+5+5+5

10+10+5+5+5+5+5+5

10+5+5+5+5+5+5+5+5

5+5+5+5+5+5+5+5+5+5

If you are adding the numbers 5+5+5+5+5+5+5+6+6+6, the answer is 53.

(5+5) + (5-5) + (5 + 5 - 5) + (5 x 0) =

10 + 0 + 5 + 0 = 15

Not all numbers are possible and for some numbers there are several solutions. Here are some examples:

0: (5x5)-(5x5)

1: (5:5)+5-5

2: (5:5)+(5:5)

3: (5+5+5):5

4: [(5x5)-5]:5

5: [(5-5)x5]+5

6: [(5x5)+5]:5

7: [(5+5):5]+5

10: 5+5+5-5

11: (5:5)+5+5

15: (5x5)-5-5

20: 5+5+5+5

24: (5x5)-(5:5)

25: (5x5)+5-5

26: (5x5)+(5:5)

30: [(5:5)+5]x5

35: (5x5)+5+5

45: [(5+5)x5]-5

50: (5x5)+(5x5)

55: [(5+5)x5]+5

75: (5+5+5)x5

120: (5x5x5)-5

130: (5x5x5)+5

625: 5x5x5x5

Well, isn't that a happy little math problem! You can make 75 cents using a combination of these coins by using one quarter (25 cents), one nickel (5 cents), and three dimes (10 cents each). Just like painting a beautiful landscape, sometimes it's all about finding the right balance and combination of elements to create something wonderful.

5

5 - 5 + 5 - 5 + 5 = 5

5 + 5 - 5 - 5 + 5 =5

5 + 5 + 5 + 5 X 5 = 100

5

5 + 5 - 5 - 5 + 5 + 5 = 10

(5 + 5) x 5/5 x 5/5 = 10

12 1) 20 + 20 + 10 2) 20 + 20 + 5 + 5 3) 20+ 10 + 10 + 10 4) 20 + 10 + 10 + 5 + 5 5) 20 + 10 + 5 + 5 + 5 + 5 6) 20 + 5 + 5 + 5 + 5 + 5 + 5 7) 10 + 10 + 10 + 10 + 10 8) 10 + 10 + 10 + 10 + 5 + 5 9) 10 + 10 + 10 + 5 + 5 + 5 + 5 10) 10 + 10 + 5 + 5 + 5 + 5 + 5 + 5 11) 10 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 12) 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5

((5+5) x (5) - (5))/(5)

Solving steps:

5 + 5 = 10

10 x 5 = 50

50 -5 = 45

45/5 = 9

5+5-5/5

It is: 5*5-55-5 = 24

(5 + 5) × (5 + 5) = 100

5-5+5-5+5 equal to 5

The numerals 5 5 5 5 can be arranged as 55 + 5/5 = 56.