(2+2)/(2+2)=1

(2/2)+(2/2)=2

(2*2)-(2/2)=3

(2+2+2)-2=4

(2+2)+(2/2)=5

(2*2*2)-2=6

((2-.2)/.2)+2=7

2+2+2+2=8

(22/2)+2=9

((2+2)*2)+2=10

((2-.2)/.2)+2=11

(2+2+2)*2+=12

(22/2)+2=13

(2/.2)+(2+2)=14

2+(2/2)/.2=15

(2+2)*(2+2)=16

...??????????=17

((2+2)/.2)-2=18

((2+2)-.2)/.2=19

22- √(2+2)=20

230.
2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2 = 1073741824

21

As a fraction it is: 2/9

256

2, 128

2, 2, 64

2, 2, 2, 32

2, 2, 2, 2, 16

2, 2, 2, 2, 2, 8

2, 2, 2, 2, 2, 2, 4

2, 2, 2, 2, 2, 2, 2, 2

8192

32

2+2+2+2+2+2+2+2+2+2+2+2+(2x0)

=2+2+2+2+2+2+2+2+2+2+2+2+0

=24

2+2+2=6

2 * 2 * 2 * 2 * 2 * 2 * 2, or 27.

Broken down as follows.....

128

2, 64

2, 2, 32

2, 2, 2, 16

2, 2, 2, 2, 8

2, 2, 2, 2, 2, 4

2, 2, 2, 2, 2, 2, 2

128

2*64

2*2*32

2*2*2*16

2*2*2*2*8

2*2*2*2*2*4

2*2*2*2*2*2*2

2^7

2 + 2 - 2 = 2 or 2+(2-2)=2+0=2

128

2, 64

2, 2, 32

2, 2, 2, 16

2, 2, 2, 2, 8

2, 2, 2, 2, 2, 4

2, 2, 2, 2, 2, 2, 2

2 + 23 = 25

3 + 3 + 19 = 25

3 + 5 + 17 = 25

3 + 11 + 11 = 25

5 + 7 + 13 = 25

7 + 7 + 11 = 25

2 + 2 + 2 + 19 = 25

2 + 2 + 2 + 2 + 17 = 25

2 + 2 + 2 + 2 + 2 + 2 + 13 = 25

2 + 2 + 2 + 2 + 2 + 2 + 2 + 11 = 25

2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 7 = 25

2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 5 = 25

2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 3 = 25

800

2, 400

2, 2, 200

2, 2, 2, 100

2, 2, 2, 2, 50

2, 2, 2, 2, 2, 25

2, 2, 2, 2, 2, 5, 5

480

2, 240

2, 2, 120

2, 2, 2, 60

2, 2, 2, 2, 30

2, 2, 2, 2, 2, 15

2, 2, 2, 2, 2, 3, 5

2+2+2+2+2+2+2+2+2+2+2+2

Its 4 ;p

40

-1+(2x9)=17

1 and 9 are not twos.

How about this: (2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2) /2 = 17

They are opposite parallel lines with points of (-2, 2) (2, 2) and (-2, -2) (2, -2)

210 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 =1,024
1024

LCM factoring

512=2*2*2*2*2*2*2*2*2

648=2*2*2*2*3*3*3*3

lcm=2*2*2*2*2*2*2*2*2*3*3*3*3=41,472

2

The answer is 0 because at the end it is multiplied by 0

2

Negative numbers do not have prime factorizations.

192

2, 96

2, 2, 48

2, 2, 2, 24

2, 2, 2, 2, 12

2, 2, 2, 2, 2, 6

2, 2, 2, 2, 2, 2, 3

you can break 800 in

2*2*2*2*2*5*5 = 2^5 * 5^2

so its divisible by any combination of multiplying numbers 2,2,2,2,2,5,5 where you can you only one in each combo.

so:

1

2

2*2=4

2*2*2=8

2*2*2*2=16

2*2*2*2*2=32

2*5=10

2*2*5=20

2*2*2*5=40

2*2*2*2*5=80

2*2*2*2*2*5=160

2*5*5=50

2*2*5*5=100

2*2*2*5*5=200

2*2*2*2*5*5=400

2*2*2*2*2*5*5=800

5

5*5=25

2*2*2*2*2*2*2*2*2*2=1024

2^10 = 1024

Gcf

32=2*2*2*2*2

56=2*2*2*7

64=2*2*2*2*2*2

gcf=2*2*2 =8

2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 * 23 = 23552

1/2 + (11/2)*2 = 1/2 + (3/2)*2 = 1/2 + 3 = 31/2

1/2 + (11/2)*2 = 1/2 + (3/2)*2 = 1/2 + 3 = 31/2

1/2 + (11/2)*2 = 1/2 + (3/2)*2 = 1/2 + 3 = 31/2

1/2 + (11/2)*2 = 1/2 + (3/2)*2 = 1/2 + 3 = 31/2

2*2*2*2*2*2*2*2*2*3

It is: (2+2+2)*2 = 12

(2/2) times (2/2)

(2/2) divided by (2/2)

22 divided by 22

(2 + 2) / (2 + 2)

1,000,000

1,000, 1,000

2, 500, 2, 500

2, 2, 250, 2, 2, 250

2, 2, 2, 125, 2, 2, 2, 125

2, 2, 2, 5, 25, 2, 2, 2, 5, 25

2, 2, 2, 5, 5, 5, 2, 2, 2, 5, 5, 5

Listed in order ...2, 2, 2, 2, 2, 2, 5, 5, 5, 5, 5, 5

By multiplication

21 = 2

22 = 2 x 2 = 4

23 = 2 x 2 x 2 = 8

24 = 2 x 2 x 2 x 2 = 16

25 = 2 x 2 x 2 x 2 x 2 = 32

26 = 2 x 2 x 2 x 2 x 2 x 2 = 64

27 = 2 x 2 x 2 x 2 x 2 x 2 x 2 = 128

28 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 = 256

29 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 = 516

96

2, 48

2, 2, 24

2, 2, 2, 12

2, 2, 2, 2, 6

2, 2, 2, 2, 2, 3

400

200, 2

100, 2, 2

50, 2, 2, 2

25, 2, 2, 2, 2

5, 5, 2, 2, 2, 2

4

I'm not sure if you're allowed to do this, but here goes

Factor the !@#$ out of EVERYTHING

2, 2, 2, 2, 2, 2, 2, 2, 2, 2

Cool, alright, let's get it on.

(((2*2*2*2)+2+2+2+(2/2))-2

16+6+1-2

16+7-2

23-2

21

256 = 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 = 2^8

64=8*8

4*2 4*2

2*2 2*2 the answer is:2*2*2*2*2*2