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Equation of any circle, with any radius, and its center at any point:

[ x - (x-coordinate of the center) ]2 + [ y - (y-coordinate of the center) ]2 = (radius of the circle)2

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The standard equation of a circle, with center in (a,b) and radius r, is:

(x-a)2 + (y-b)2 = r2

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This equation cannot be answered. You will have to give me more detail on this equation.

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The equation of the circle is: x^2 + y^2 = 81

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The arrow, which represents "produces" or "yields".

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The equation is: (x+3)^2 +(y+5)^2 = 16

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Its equation is: (x-3.2)^2+(y+2.1)^2 = 18.49

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Well, honey, the center of that circle is simply the point (3, 9). You see, the equation you provided is in the form (x - h)² + (y - k)² = r², where (h, k) is the center of the circle. So, in this case, the center is at (3, 9). That's all there is to it, sugar.

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The equation of the circle is: (x+3.2)^2 +(y+2.1)^2 = 18.49

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Equation of circle: (x-2)^2 +(y+9)^2 = 49

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The equation of circle is (x−h)^2+(y−k)^2 = r^2, where h,k is the center of circle and r is the radius of circle.

so, according to question center is origin and radius is 10,

therefore, equation of circle is x^2 + y^2 = 100

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The general equation of a circle is given by the formula

(x - h)2 + (x - k)2 = r2, where (h, k) is the center of the circle, and r its radius.

Since the center of the circle is (0, 0), the equation reduces to

x2 + y2 = r2

So that the equation of our circle is x2 + y2 = 36.

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The equation of a circle can be written in the form (x-h)2 + (y - k)2 = r2, where r is the radius, and (h,k) is the center.

So for your example, the equation would be:

(x- 5)2 + (y - 3)2 = 72

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x2 + y2 = r2, where r is the radius.

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Equation of a circle is given by:

(x-a)2 + (y-b)2 = r2

Here a & b are the coordinates of the center.

So, a = -3 & b = 6. And r = 10.

Thus, the equation formed is (x+3)2+(y-6)2 = 102

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The center of the circle is at (9, 7) on the Cartesian plane

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The center of the circle given by the equation (x - 3)2 plus (y + 2)2 = 9 is (3,-2).

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The general equation for the circle - or one of them - is:

(x - a)^2 + (y - b)^2 = r^2

Where:

a and b are the coordinates of the center

r is the radius

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Without an equality sign the given terms can't be considered to be the equation of a circle.

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What is the center of the circle given by the equation (x- 2)2 + (y + 4)2 = 6?

(2, -4)

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The equation of a circle with center (2, -3) and radius 3 can be written as (x - 2)^2 + (y + 3)^2 = 3^2.

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I assume you mean (x-7)^2 + (y + 6)^2 = 100 (using "^" for powers). Answers.com eliminates some signs, such as the equal sign.

This equation is in a form in which you can (almost) read off this information directly. A circle with equation (x - a)^2 + (y - b)^2 = r^2 has a center (a, b), and a radius of "r". In this case, just convert the original equation to:

(x - 7)^2 + (y - (-6))^2 = 10^2

And you can directly read off the coordinates of the center (7, -6), and of the radius (10).

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A unit circle is a circle of radius 1. If it's center is at the origin of an xy-coordinate system, then the equation is

x (squared) + y (squared) = 1

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By using Cartesian equations for circles on the Cartesian plane

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