Put them is ascending order.

Count them = n.

If n is odd, calculate (n+1)/2

the median is the value of the [(n+1)/2]th number in the ordered list.

If n is even, the median is the average of the [n/2]th and [n/2 + 1]th numbers.

Unfortunately, the browser used for posting questions is hopelessly inadequate for mathematics: it strips away most symbols. All that we can see is "...find Th and Th derivative of y - five cos (twox) ...". From that it is not at all clear what the missing symbols (operators) might be. I am guessing that you want the nth and (n+1)th derivatives of something like y = -5*cos(2x). I am also assuming that you are familiar with the chain rule for finding derivatives. Finally, this browser is also rubbish and I cannot show superscripts so I will use the ^ symbol to represent powers..
y = -5*cos(2x)dy/dx = -5*[-sin(2x)]*2 = 2*5*sin(2x) d^2y/dx^2 = 2*5*cos(2x)*2 = 2^2*5*cos(2x)d^3y/dx^3 = 2^2*5*[-sin(2x)]*2 = -2^3*5*sin(2x) d^4y/dx^4 = -2^3*5*cos(2x)*2 = -2^4*5*cos(2x) = 2^4*y

So,for n = 1, 5, 9 ... [n = 1 mod(4)]: d^ny/dx^n = 2^n*5*sin(2x) = 2^n*5*cos(pi/2 - 2x)for n = 2, 6, 10 ... [n = 2 mod(4)]: d^ny/dx^n = 2^n*5*cos(2x) = -2^n*y
for n = 3, 7, 11 ... [n = 3 mod(4)]: d^ny/dx^n = -2^n*5*sin(2x) = -2^n*5*cos(pi/2 - 2x)
for n = 4, 8, 12 ... [n = 0 mod(4)]: d^ny/dx^n = -2^n*5*cos(2x) = 2^n*y

the (n-1)th term plus the (n-2)th term.

2 n in a d is 2 = nickels in a dime.

'Firme(n)/firma(d) este papel'. (formal/informal(plural))

(FEARmay(n)/FEARmah(th) ESStay pahPELL) ('th' as in 'they')

The nth triangular number is n(n+1)/2

Kat Von D's tattoo shop is located at: 1259 N. La Brea Ave. W. Hollywood, Ca. 90038.

Pick one

1: for (i=2*n-1; i>=1; i-=2) printf ("%d\n", i);

2: for (i=n; i>=1; i--) printf ("%d\n", 2*i-1);

3: for (i=0; i<n; i++) printf ("%d\n", 2*(n-i)-1);

No, Kat Von D is not single.

T(n) = 5n + 16

Sum = n/2[2Xa1+(n-1)d] where n is last number, a1 is the first number & d is the common difference between the numbers, here d=2 for the even /odd numbers. Sum = n/2 [2Xa1+(n-1)2]

There are 22 ways to make change from a dollar using nickels, dimes, and quarters.

1. 4 q

2. 10 d

3. 20 n

4. 2 q , 5 d

5. 3 q , 2 d , 1 n

6. 1 q , 7 d, 1 n

7. 9 d, 2 n

8. 8 d, 4 n

9. 7 d, 6 n

10. 6 d , 8 n

11. 5 d , 10 n

12. 4 d , 12 n

13. 2 d , 16 n

14. 1 d , 18 n

15. 5 n , 3 q

16. 3 n , 1 q , 6 d

17. 7 n , 1 q , 4 d

18. 9 n , 1 q , 3 d

19. 11 n , 1 q , 2 d

20. 13 n , 1 q , 1 d

21. 14n , 3 d

22. 15n , 1 q

The sum of an arithmetical sequence whose nth term is

U(n) = a + (n-1)*d is

S(n) = 1/2*n*[2a + (n-1)d]

or 1/2*n(a + l) where l is the last term in the sequence.

Use the following formula:

an = a1 + (n - 1)d, where

a1 = the first term

n = the n th term (general term)

d = common difference (which is constant between terms)

Since we need to find the 14 th term, we can write:

a1 = 100

n = 14

d = -4

an = a1 + (n - 1)d

a14 = 100 + (14 - 1)(-4)

a14 = 100 + (13)(-4)

a14 = 100 - 52

a14 = 48

Thus, the 14 th term is 48.

Assuming nickles, dimes, and quarters, there are ten different ways to make change for a half dollar. Just enumerate the combinations...

10 n

8 n 1 d

6 n 2 d

4 n 3 d

2 n 4 d

5 d

5 n 1 q

3 n 1 d 1 q

1 n 2 d 1 q

2 q

d = n + 7 and (n + 17)/(d - 6) = 2 so (n + 17)/ n + 7 - 6 = 2 (n + 17)/(n + 1) = 2 2n + 2 = n + 17 n = 15 and d = 22 Check n + 17 = 32, d - 6 = 16, 32/16 = 2 Original number is 15/22

1 q 1 d

1 q 2 n

2 d 3 n

3 d 1 n

1 d 5 n

7 n

In a sequence of numbers, a(1), a(2), a(3), ... , a(n), a(n+1), ...

he first differences are a(2) - a(1), a(3) - a(2), ... , a(n+1) - a(n) , ...

Alternatively, d the sequence of first differences is given by

d(n) = a(n+1) - a(n), n = 1, 2, 3, ...

A fraction, n/d, in percentage terms is simply (100*n) / d. In this case, n = 2 and d = 3.

Mean = sum of observations/number of observations

Median: Order the observations. Of there are an odd number of observations, the median is the middle one. So if there are n observations (where n is odd) then the median is the (n+1)/2 th observation. If n is even, the median is the average of the n/2 th observation and the (n/2 +1) th.

Mode: Group the observations. The mode is the value or values that appear the most often. There may be no mode, a single mode or lots of them.

Kat Von D is bisexual.

Kat Von D is bisexual.

Let n (i) = the term number of each term in the sequence., with (i) going from 1-6 E.g term number 1 (n (1) ) is 3. n(2)= -7 etc...

Therefore n(i) for odd terms in the sequence is n (i)= (n (i -2)th term +1).

For even terms in the sequence, n(i)= (n (i - 2)th term -3).

P(2x3) - 1/4

where P(n) is the n-th prime.

// transpose for the sparse matrix void main() { clrscr(); int a[10][10],b[10][10]; int m,n,p,q,t,col; int i,j; printf("enter the no of row and columns :\n"); scanf("%d %d",&m,&n); // assigning the value of matrix for(i=1;i<=m;i++) { for(j=1;j<=n;j++) { printf("a[%d][%d]= ",i,j); scanf("%d",&a[i][j]); } } printf("\n\n"); //displaying the matrix printf("\n\nThe matrix is :\n\n"); for(i=1;i<=m;i++) { for(j=1;j<=n;j++) { printf("%d\t",a[i][j]); } printf("\n"); } t=0; printf("\n\nthe non zero value matrix are :\n\n"); for(i=1;i<=m;i++) { for(j=1;j<=n;j++) { // accepting only non zero value if(a[i][j]!=0) { t=t+1; b[t][1]=i; b[t][2]=j; b[t][3]=a[i][j]; } } } printf("a[0 %d %d %d\n",m,n,t); for(i=1;i<=t;i++) { printf("a[%d %d %d %d\n",i,b[i][1],b[i][2],b[i][3]); } a[0][1]=n; a[0][2]=m; a[0][3]=t; int s[10],u[10]; if(t>0) { for(i=1;i<=n;i++) { s[i]=0; } for(i=1;i<=t;i++) { s[b[i][2]]=s[b[i][2]]+1; } u[1]=1; for(i=2;i<=n;i++) { u[i]=u[i-1]+s[i-1]; } for(i=1;i<=t;i++) { j=u[b[i][2]]; a[j][1]=b[i][2]; a[j][2]=b[i][1]; a[j][3]=b[i][3]; u[b[i][2]]=j+1; } } printf("\n\n the fast transpose matrix \n\n"); printf("a[0 %d %d %d\n",n,m,t); for(i=1;i<=t;i++) { printf("a[%d %d %d %d\n",i,a[i][1],a[i][2],a[i][3]); } getch(); }

Kat Von D real name is: Katherine Von Drachenberg

d = 2
(n = 265782341)

2 nickels in a dime

This can be found out by using the formula for sum of n terms of an arithmetic progression.

here,

n is not known.

a=2

d=2 (since it's even)

nth term=98 (last even number less than 100)

using formula for nth term,

nth term=a+(n-1)d

98=2+(n-1)2

therefore, n=49

so, sum of n terms=n/2[2*a+(n-1)d]

putting n=49, a=2, and d=2,

sum=2450

T i t s a n d a s s, mmmmm in my m o u th

This is the Fibonacci sequence, where the number is the sum of the two preceding numbers. The nth term is the (n-1)th term added to (n-2)th term

Kat Von D lives in Los Angeles, California.

#include

void main()

{

int i=2,m,n;

printf("enter number");

scanf("%d",&n);

do

{

m=i*n;

printf("%d*%d=%d\n",n,i,m);

i=i+1;

}

while (i<=10);

}

J. D. Th Wassenaar has written:

'\\'

D. H. Th. Vollenhoven was born in 1892.

D. H. Th. Vollenhoven died in 1978.

Kat Von D is worth More$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$

Kat Von D has a Blackberry Curve.

Yes, Kat Von D has 1 kids

Kat Von D has 1 child

The sum of a sequence is given by sum = n/2(2a + (n-1)d) where:

n = how many

a = first number of sequence

d = difference between terms of sequence.

For the first 22 odd numbers these are:

n = 22

a = 1

d = 2

→ sum = 22/2(2×1 + (22 - 1)×2)) = 22² = 484

The sum of the first n odd numbers is always n²:

sum = n/2(2×1 + (n-1)2) = n/2(1 + (n-1))×2 = n(n) = n²

• Group 3: ns^2 (n-1)d^1
• Group 4: ns^2 (n-1)d^2
• Group 5: ns^2 (n-1)d^3
• Group 6: ns^1 (n-1)d^5
• Group 7: ns^1 (n-1)d^6

Kat Von D married to Oliver Peck from 2003 to 2007 Kat Von D married to Rafael Reyes in 2018

2 raised to the power of n+1. In other words 2 multiplied by itself n+1 times.

London

Kat von D specializes in giving tattoos. Kat von D has had television shows showing her tattoo shop and her workers giving tattoos. Kat von D has over a dozen tattoos on her body.

int maxprod (int n)

{

return n/2;

}

int main (void)

{

int n, a, b;

n= 7; /* for example */

a= maxprod (n);

b= n-a;

printf ("%d+%d=%d, %d*%d=%d\n", a, b, a+b, a, b, a*b);

}

Kat von d is half German half Latino

Kat Von D was born on March 8, 1982.