I try to get data on the structure of beta-cristobalite, SiO2. On I find the following:

Cristobalite Downs R T, Palmer D C American Mineralogist 79 (1994) 9-14 The pressure behavior of alpha cristobalite P = room pressure _database_code_amcsd 0001629 4.9717 4.9717 6.9223 90 90 90 P4_12_12 atom x y z B(1,1) B(2,2) B(3,3) B(1,2) B(1,3) B(2,3) Si .30028 .30028 0 .0077 .0077 .00401 -.0003 .0008 -.0008 O .2392 .1044 .1787 .0244 .0086 .0062 -.0013 .0027 .0005

I have no idea what this means. I know the unit cell should have 4 Si atoms, and each should bond to 4 O atoms. What information is given from these numbers (all of them)?

Silica is made out of silicon and oxygen atoms bonded together, forming a compound known as silicon dioxide. Silicon dioxide is the most common constituent of the Earth's crust and is found in various forms, such as quartz, sand, and glass.

Yes. Volcanic ash falls into the air pollutant category of particulate matter. It can cause respiratory and eye symptoms during and after ash fall. The ash contains the minerals quartz, cristobalite, or tridymite. These are free crystalline silica which may cause silicosis which is a disabling and potential fatal lung disease. The recommended respirable exposure limit of 50 ug/m3 of particulate in air can be exceeded for short periods of time.

A polymorph is defined as same composition, different chemical structures. Quartz, cristobalite, and tridymite are examples of polymorph because they are three different minerals with the same chemical composition. Graphite and diamond are also good examples of polymorphism. They both contain carbon atoms, but they have extremely different properties because of the condition in which they formed. Diamond forms where extreme pressures and temperatures produce its compact structure. On the other hand, graphite forms under comparatively low pressures and it has weekly bonded carbon sheets that create its greasy feel. The difference in conditions makes diamond much harder than graphite and graphite much more useful as a lubricant.

(2+2)/(2+2)=1

(2/2)+(2/2)=2

(2*2)-(2/2)=3

(2+2+2)-2=4

(2+2)+(2/2)=5

(2*2*2)-2=6

((2-.2)/.2)+2=7

2+2+2+2=8

(22/2)+2=9

((2+2)*2)+2=10

((2-.2)/.2)+2=11

(2+2+2)*2+=12

(22/2)+2=13

(2/.2)+(2+2)=14

2+(2/2)/.2=15

(2+2)*(2+2)=16

...??????????=17

((2+2)/.2)-2=18

((2+2)-.2)/.2=19

22- √(2+2)=20

230.
2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2 = 1073741824

21

As a fraction it is: 2/9

256

2, 128

2, 2, 64

2, 2, 2, 32

2, 2, 2, 2, 16

2, 2, 2, 2, 2, 8

2, 2, 2, 2, 2, 2, 4

2, 2, 2, 2, 2, 2, 2, 2

8192

32

2+2+2+2+2+2+2+2+2+2+2+2+(2x0)

=2+2+2+2+2+2+2+2+2+2+2+2+0

=24

2+2+2=6

2 * 2 * 2 * 2 * 2 * 2 * 2, or 27.

Broken down as follows.....

128

2, 64

2, 2, 32

2, 2, 2, 16

2, 2, 2, 2, 8

2, 2, 2, 2, 2, 4

2, 2, 2, 2, 2, 2, 2

128

2*64

2*2*32

2*2*2*16

2*2*2*2*8

2*2*2*2*2*4

2*2*2*2*2*2*2

2^7

2 + 2 - 2 = 2 or 2+(2-2)=2+0=2

128

2, 64

2, 2, 32

2, 2, 2, 16

2, 2, 2, 2, 8

2, 2, 2, 2, 2, 4

2, 2, 2, 2, 2, 2, 2

2 + 23 = 25

3 + 3 + 19 = 25

3 + 5 + 17 = 25

3 + 11 + 11 = 25

5 + 7 + 13 = 25

7 + 7 + 11 = 25

2 + 2 + 2 + 19 = 25

2 + 2 + 2 + 2 + 17 = 25

2 + 2 + 2 + 2 + 2 + 2 + 13 = 25

2 + 2 + 2 + 2 + 2 + 2 + 2 + 11 = 25

2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 7 = 25

2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 5 = 25

2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 3 = 25

800

2, 400

2, 2, 200

2, 2, 2, 100

2, 2, 2, 2, 50

2, 2, 2, 2, 2, 25

2, 2, 2, 2, 2, 5, 5

480

2, 240

2, 2, 120

2, 2, 2, 60

2, 2, 2, 2, 30

2, 2, 2, 2, 2, 15

2, 2, 2, 2, 2, 3, 5

2+2+2+2+2+2+2+2+2+2+2+2

Its 4 ;p

40

-1+(2x9)=17

1 and 9 are not twos.

How about this: (2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2) /2 = 17

They are opposite parallel lines with points of (-2, 2) (2, 2) and (-2, -2) (2, -2)

210 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 =1,024
1024

LCM factoring

512=2*2*2*2*2*2*2*2*2

648=2*2*2*2*3*3*3*3

lcm=2*2*2*2*2*2*2*2*2*3*3*3*3=41,472

2

The answer is 0 because at the end it is multiplied by 0

2

Negative numbers do not have prime factorizations.

192

2, 96

2, 2, 48

2, 2, 2, 24

2, 2, 2, 2, 12

2, 2, 2, 2, 2, 6

2, 2, 2, 2, 2, 2, 3

you can break 800 in

2*2*2*2*2*5*5 = 2^5 * 5^2

so its divisible by any combination of multiplying numbers 2,2,2,2,2,5,5 where you can you only one in each combo.

so:

1

2

2*2=4

2*2*2=8

2*2*2*2=16

2*2*2*2*2=32

2*5=10

2*2*5=20

2*2*2*5=40

2*2*2*2*5=80

2*2*2*2*2*5=160

2*5*5=50

2*2*5*5=100

2*2*2*5*5=200

2*2*2*2*5*5=400

2*2*2*2*2*5*5=800

5

5*5=25

2*2*2*2*2*2*2*2*2*2=1024

2^10 = 1024

Gcf

32=2*2*2*2*2

56=2*2*2*7

64=2*2*2*2*2*2

gcf=2*2*2 =8

2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 * 23 = 23552

1/2 + (11/2)*2 = 1/2 + (3/2)*2 = 1/2 + 3 = 31/2

1/2 + (11/2)*2 = 1/2 + (3/2)*2 = 1/2 + 3 = 31/2

1/2 + (11/2)*2 = 1/2 + (3/2)*2 = 1/2 + 3 = 31/2

1/2 + (11/2)*2 = 1/2 + (3/2)*2 = 1/2 + 3 = 31/2

2*2*2*2*2*2*2*2*2*3

It is: (2+2+2)*2 = 12

(2/2) times (2/2)

(2/2) divided by (2/2)

22 divided by 22

(2 + 2) / (2 + 2)

1,000,000

1,000, 1,000

2, 500, 2, 500

2, 2, 250, 2, 2, 250

2, 2, 2, 125, 2, 2, 2, 125

2, 2, 2, 5, 25, 2, 2, 2, 5, 25

2, 2, 2, 5, 5, 5, 2, 2, 2, 5, 5, 5

Listed in order ...2, 2, 2, 2, 2, 2, 5, 5, 5, 5, 5, 5

By multiplication

21 = 2

22 = 2 x 2 = 4

23 = 2 x 2 x 2 = 8

24 = 2 x 2 x 2 x 2 = 16

25 = 2 x 2 x 2 x 2 x 2 = 32

26 = 2 x 2 x 2 x 2 x 2 x 2 = 64

27 = 2 x 2 x 2 x 2 x 2 x 2 x 2 = 128

28 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 = 256

29 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 = 516

96

2, 48

2, 2, 24

2, 2, 2, 12

2, 2, 2, 2, 6

2, 2, 2, 2, 2, 3

400

200, 2

100, 2, 2

50, 2, 2, 2

25, 2, 2, 2, 2

5, 5, 2, 2, 2, 2

4