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The transverse axis is perpendicular to the conjugate axis.

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It is the conjugate axis or the minor axis.

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Graphically, the conjugate of a complex number is its reflection on the real axis.

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For example, the conjugate of 5 + 3i is 5 - 3i. The graph of the first number is three units above the real number line; the second one is three units below the real number line.

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For a complex number (a + bi), its conjugate is (a - bi). If the number is graphically plotted on the Complex Plane as [a,b], where the Real number is the horizontal component and Imaginary is vertical component, the Complex Conjugate is the point which is reflected across the real (horizontal) axis.

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The conjugate will have equal magnitude. The angle from the real axis will be the same angle measure (but opposite direction).

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The complex conjugate of a number in the form a + bi is simply the same number with the sign of the imaginary part changed. In this case, the number is 7 + 3i, so its complex conjugate would be 7 - 3i. This is because the complex conjugate reflects the number across the real axis on the complex plane.

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The conjugate acid of ClO- is HClO. The conjugate acid of HClO is ClO2. The conjugate acid of HCI is H2Cl. The conjugate acid of Cl- is HCl. The conjugate acid of ClO is HClO2.

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The conjugate base and conjugate acid for HS04 is:

Conjugate acid is H2SO4

Conjugate base is SO42

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"Conjugate" usually means that in one of two parts, the sign is changed - as in a complex conjugate. If the second part is missing, the conjugate is the same as the original number - in this case, 100.

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The conjugate acid of NO2- is HNO2 (nitrous acid).

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The conjugate acid of LiOH is considered Li+.

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The conjugate of 6 + i is 6 - i.

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The conjugate acid of H2O is H3O+ (hydronium ion). When an acid donates a proton, it forms its conjugate base, and when a base accepts a proton, it forms its conjugate acid.

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It depends on what the denominator was to start with: a surd or irrational or a complex number.

You need to find the conjugate and multiply the numerator by this conjugate as well as the denominator by the conjugate. Since multiplication is by [conjugate over conjugate], which equals 1, the value is not affected.

If a and b are rational numbers, then

conjugate of sqrt(b) = sqrt(b)

conjugate of a + sqrt(b) = a - sqrt(b), and

conjugate of a + ib = a - ib where i is the imaginary square root of -1.

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The conjugate base of NH3 is NH2-, formed by removing a proton (H+) from NH3.

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the conjugate 7-2i

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The conjugate base of HSO3- is SO32-.

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The conjugate base for CH3CH2COOH is CH3CH2COO-.

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The conjugate acid of CIO- is HClO. When CIO- gains a proton, it forms HClO as its conjugate acid.

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The conjugate acid of the base NH2OH (hydroxlyamine) is NH3OH^+

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The conjugate base of H2O is OH-. When H2O loses a proton, it forms the hydroxide ion OH-, which is the conjugate base of water.

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The conjugate base of HCO3- is CO32-.

Conjugates always differ by one H+. A conjugate base has one fewer H+, while a conjugate acid has one more H+.

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The conjugate base of H3PO4 is H2PO4-. The formula for the conjugate base can be found by removing one proton (H+) from the acid molecule.

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The conjugate of 2 + 3i is 2 - 3i, and the conjugate of 2 - 5i is 2 + 5i.

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The conjugate acid of H4N2 is H5N2+ because it gains a proton (H+) to form its conjugate acid.

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The conjugate acid of ClO^- is HClO. This is because ClO^- is a base that can accept a proton to form its conjugate acid.

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How about "-i" since "i" is just "0 + i" so the conjugate should be "0 - i" or "-i"

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semi conjugate diameter of ellipse

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depends on what the verb ends in, and what tense you want to conjugate in.

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The conjugate acid of HC6H6O6 is C6H6O6H+.

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The conjugate base of H2SO4 is HSO4-.

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The conjugate base of H2SeO4 is HSeO4-.

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The conjugate base of HAsO4^2- is H2AsO4-.

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The conjugate base of NH3 is NH2-.

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The conjugate base of HC2O4 is C2O4^2-.

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The conjugate base of HF is the fluoride ion F-

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The conjugate acid of O2- is H2O2 (hydrogen peroxide). When O2- gains a proton, it forms H2O2.

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The conjugate acid of HCO3- is H2CO3 (carbonic acid). When HCO3- gains a proton, it forms carbonic acid, which is its conjugate acid.

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For any number (a + bi), its conjugate is (a - bi), so the real part stays the same, and the imaginary part is negated.

For this one, conjugate of [-3 - 9i] is: -3 + 9i

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The conjugate base of H2SO3 is HSO3- and the conjugate acid is H3O+.

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When finding the conjugate of a binomial, you just reverse the sign. So the conjugate of 3+4i is 3-4i.

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If you are referring to conjugate acids and bases, a conjugate acid is an acid that can donate a H+ in order to form a conjugate base. For example, HCl can donate it's H+ and create the conjugate base Cl-. On the other hand, a conjugate base would just be the opposite where chloride could add a hydrogen in order to create the conjugate acid.

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The conjugate base of HNO3 is NO3-.

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The conjugate base for HSO4- is SO4^2-.

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The conjugate base of H3BO3 is B(OH)4-.

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