10000

rip version 1 is classfull routing protocol. in classfull routing protocol is not able to carry its subnet mask whatever the ip belong from a class. it wil take its by default subnet mask.if the ip address belong to class b and the subnet mask is published as /28. in classless routing protocol this ip address would be displayed as /16 not like /28

except sap all r protocol. so sap is required answer..

smtp: simple mail transfer protocol

wap: wireless application protocol

arp: address resolution protocol

sap is an enterprise software

What protocol is used by web servers and on which port ?

Transformers Robots in Disguise - 2001 Battle Protocol 1-1 was released on:

USA: 8 September 2001

Patricia B. Jensen has written:

'Historical overview of data communication with analysis of a selective repeat protocol'

1) Wireless Application Protocol

2) Wireless Access Point

3) Wireless Access Protocol.

1 tcp transmission control protocol

2 udp protocol

Assuming IPv4 ICMP. Ping uses IP for transport. Ping in itself is an "Echo Request", which is a function of the ICMP protocol. The IP Packet will carry the ICMP protocol from end-to-end.

ICMP has a protocol number of 1, so the "Protocol" field in the IPv4 header will contain "1" as a reference to the ICMP payload.

For IPv6, ICMPv6 is used, and the transport will be IPv6.

(B^-1)B = 1

B^(-1xB) = 1/(B^B)

1) SMTP- simple mail transfer protocol

2) GMTP- Group mail transfer protocol

3) FTP- File Transfer Protocol

4) TFTP- Trivial File Transfer Protocol

5) User Process

A protocol is a set of rules for describing how to successfully exchange information between two systems.

b*1/b=1

You can cite it as an article from the UNFCCC website.

"Kyoto Protocol." United Nations Framework Convention on Climate Change. Web. 26 Nov. 2009. .

SSH uses such port.

POP

-1, because

if you factor out -1 from a-b you get -1(-a+b). when you reduce, -a+b = b-a so those cancel out and you are left with -1

- In your own words, define the term 'protocol' and what is the difference between

protocol and protocol suite

Well it has 2 meanings

1. file transfer protocol

2. If your George Lopez it means F*** that Puto!

b+b+b+b+b is equal to 5b. That is because there are five b's being added up. 1+1+1+1+1 is 5 because there are five 1's being added up.

By definition (-1)*(-1)=1.
(-a)*(-b)
(-1)*(a)*(-1)*(b)
(-1)*(-1)*(a)*(b)
(a)*(b) ■

CAN protocol is synchronous, as it relies on a fixed timing mechanism for communication between nodes. This timing mechanism establishes when messages can be transmitted and ensures they arrive at the intended recipient without delays.

9 and 10

First the main formulas:

a+b=19

a-b=1

Find out what one of the variables are.

We can choose "a" or "b" from either of the two formulas.

Let's choose "a" from the a-b=1 formula.

a - b = 1 [formula]

a-b (+b) = 1 (+b) [solve for "a" by removing "b"]

a = 1+b

Plug that "a" into the other formula a+b=19.

a + b = 19

(1+b) +b = 19

1 + 2b = 19

1 + 2b - 1 = 19 -1

2b = 18

b = 9

Plug that into our formula solved from before for "a"

a = 1 + b

a = 1 + (9)

a = 10

from 1 through 3

i believe (not quite sure) that it is at the application layer (layer 1)

There are various protocols

ftp: file transfer protocol

smtp: simple mail transfer protocol

pop3: post office protocol

ip: internet protocol

tcp: transmission control protocol

ospf: open shortest path first

igrp: interior gateway routing protocol

eigrp: enhanced interior gateway routing protocol

rip: routing information protocol

http: hyper text transfer protocol

udp: user datagram protocol

icmp: internet control message protocol

HTML is a protocol

A protocol can be defined as a set of rules determining the format and transmission of data or a set of rules that governs data communication. A protocol defines what is going to be communicated.

The key elements of protocol are

1. Syntax

2.Semantics

3.Timing

Routing Information Protocol (RIP) and Interior Gateway Routing Protocol (IGRP) are two very popular Distance Vector routing protocols

one a/b X b/a = a/a X b/b =1/1 = 1

The answer is Protocol's. Protocol is the set of rules for formatting the data across the network.

b- handles call setup, call routing, and call termination

If we have y=a(b)^t as the equation then take b from this equation

case !: If b <1

then b=1-r

r=1-b

this r is the decay factor

case 2:If b >1

then b=1+r

r=b-1

this is the growth factor

Oh, dude, B to the power of -1 is just 1 divided by B. It's like flipping B upside down and giving it a little math makeover. So yeah, B to the power of -1 equals 1/B. Math can be pretty chill sometimes, you know?

Multiplicative identity
a*1 = a

Reciprocality
a * b = 1
then a and b are reciprocals: a = 1/b and b = 1/a

Associativity
a * (b * c) = (a * b) * c

Commutativity
a * b = b * a

Distributivity
a * (b + c) = a*b + a*c

b(b^2 + 1)(b^4 - b^2 + 1)

OSPF is a classless link-state routing protocol.

RIP version 1 and IGRP are both classful distance vector routing protocols, EIGRP is a hybrid protocol that supports classless addressing.

A set of rules used for transferring data over the Internet is called a "protocol".
Hypertext transfer protocol, HTTP.

8b^2 -9b +1

8b^2 -8b -b +1

8b(b-1) - 1(b-1)

(8b-1)(b-1)

A hypertext protocol is a protocol relating to hypertext.

The most well-known hypertext-related protocol would be the Hypertext Transfer Protocol, which is used to transfer hypertext from one machine to another.

B + 1 or B - 1

PPPis more secure than SLIP. PPP uses two authetication Protocols :

1. Password Authetication Protocol (PAP)

2. Challenge Handshake Authetication Protocol (CHAP)

So if you use SLIP on network that unauthorized user can gain acces to.

1/a = 1/b: cross multiplying gives a = b

It must be x*(x+1).

To see this, suppose that there existed a smaller common multiple formed by taking

a*x and b*(x+1),

where a =/= b since multiplying by the same number won't give you a common multiple.

Then we have

a*x < x*(x+1) => a < (x+1)

b*(x+1) < x*(x+1) => b < x

=> a*b < x*(x+1).

Also, a*x = b*(x+1) => x = b/(a-b) & (x+1) = a/(a-b). Therefore

x*(x+1) = a*b/(a-b)^2 < x*(x+1)/(a-b)^2

=> (a-b)^2 < 1

=> (a-b) < 1.

The problem here is that this requires that a=b, which cannot be. Therefore, x*(x+1) is the smallest common multiple of both x and (x+1)

An example would be HTTP

a protocol that's ramdom.

Point-to-Point Protocol

no

The answer is b+1. Therefore the algebraic expression for this is b+1

b + 1 is b plus 1 as an algebraic expression.